为什么这个测试用例失败？

Question

我正在尝试将干净的体系结构和TDD纳入我的项目。因此，我正在测试用例是否返回期望的数据。但是下面的测试用例对我来说是失败的。

void main() {
  GetWordDescription useCase;
  WordRepository repository;

  setUp(() {
    repository = new MockGetWordDescription();
    useCase = new GetWordDescription(repository);
  });

  final tWord = 'lexicon';
  final tWordMap = /* word class initialization */;
  //fixme test cases failing
  test('should get List of words from the repository', () async {
    when(repository.getAll())
        .thenAnswer((realInvocation) async => Right([tWordMap]));
    final result = await useCase.getAll();
    expect(result, equals(Right<Failure, List<Word>>([tWordMap])));
    verify(repository.getAll());
    verifyNoMoreInteractions(repository);
  });
}

而且我不太确定自己在做什么错。Word类是简单的Equatable类的实例。

class Word extends Equatable {

  /* class fields */

  @override
  List<Object> get props => [/* class fields */];
}

它显示以下输出

Expected: Right<Failure, List<Word>>:<Right([Word])>
  Actual: Right<Failure, List<Word>>:<Right([Word])>

Answer 1

列表的两个实例不相等。因此，repository.getAll（）返回的[tWord]与usecase.getAll（）返回的[tWord]不相等。

我通过将列表提取到变量中并在两种情况下都使用它来解决此问题。

var tAllBooks = [tWordMap,/* more books */];

test('should get List of words from the repository', () async {
  when(repository.getAll())
      .thenAnswer((realInvocation) async => Right(tAllBooks));
  final result = await useCase.getAll();
  expect(result, equals(Right(tAllBooks)));
  verify(repository.getAll());
  verifyNoMoreInteractions(repository);
});