我实际上有3个问题。
我有一个按钮,它调用一个外部函数(下面给出的代码示例)。当我按下运行按钮,并且功能正在执行时。我想在窗口中显示从该函数到Qlabel的消息。到目前为止,当函数完全执行并返回到主函数时,我会显示该消息。但我想看看功能执行过程中。有没有办法解决?
其次,当我的GUI执行任何外部功能时,它会进入“不响应”模式。这可能是什么原因以及解决方法?
当我以任何其他分辨率(ScreenSize)打开GUI时,我想动态调整所有小部件的大小。现在,无论如何,QTablewidget的大小都是固定的。我怎么才能得到它? QTDesigner中的任何设置都可以实现?
UI设计器生成的代码:
from PyQt5 import QtCore, QtGui, QtWidgets
class Ui_MainWindow(object):
def setupUi(self, MainWindow):
MainWindow.setObjectName("MainWindow")
MainWindow.resize(1150, 905)
self.centralwidget = QtWidgets.QWidget(MainWindow)
self.centralwidget.setObjectName("centralwidget")
self.pushButton = QtWidgets.QPushButton(self.centralwidget)
self.pushButton.setGeometry(QtCore.QRect(290, 820, 161, 41))
self.pushButton.setObjectName("pushButton")
self.tableWidget = QtWidgets.QTableWidget(self.centralwidget)
self.tableWidget.setGeometry(QtCore.QRect(10, 10, 1131, 791))
self.tableWidget.setObjectName("tableWidget")
self.tableWidget.setColumnCount(0)
self.tableWidget.setRowCount(0)
self.label = QtWidgets.QLabel(self.centralwidget)
self.label.setGeometry(QtCore.QRect(580, 820, 191, 41))
self.label.setText("")
self.label.setObjectName("label")
MainWindow.setCentralWidget(self.centralwidget)
self.statusbar = QtWidgets.QStatusBar(MainWindow)
self.statusbar.setObjectName("statusbar")
MainWindow.setStatusBar(self.statusbar)
self.retranslateUi(MainWindow)
QtCore.QMetaObject.connectSlotsByName(MainWindow)
def retranslateUi(self, MainWindow):
_translate = QtCore.QCoreApplication.translate
MainWindow.setWindowTitle(_translate("MainWindow", "MainWindow"))
self.pushButton.setText(_translate("MainWindow", "Run"))
if __name__ == "__main__":
import sys
app = QtWidgets.QApplication(sys.argv)
MainWindow = QtWidgets.QMainWindow()
ui = Ui_MainWindow()
ui.setupUi(MainWindow)
MainWindow.show()
sys.exit(app.exec_())
主脚本:
from PyQt5 import QtWidgets
from demoUI import Ui_MainWindow
from callingexternalfunction import callingexternalfunction
class DemoCode(QtWidgets.QMainWindow, Ui_MainWindow):
def __init__(self):
super(DemoCode, self).__init__()
self.setupUi(self)
self.pushButton.clicked.connect(self.button_clicked)
def button_clicked(self):
callingexternalfunction(self)
if __name__ == "__main__":
import sys
app = QtWidgets.QApplication(sys.argv)
window = DemoCode()
window.show()
sys.exit(app.exec_())
函数调用外部函数:
import time
def callingexternalfunction(self):
for i in range(0,5):
time.sleep(3)
self.label.setText('3 Second Pause '+ str(i))
问题1和2相关,所以我将一起解决它们:
GUI冻结,因为睡眠功能阻止了GUI事件循环,因此逻辑是在另一个线程中运行它。另一方面,由于GUI不是线程安全的,因此无法直接从另一个线程访问GUI,因此必须使用信号。
main.py
from PyQt5 import QtCore, QtWidgets
import threading
from demoUI import Ui_MainWindow
from callingexternalfunction import callingexternalfunction
class DemoCode(QtWidgets.QMainWindow, Ui_MainWindow):
signal = QtCore.pyqtSignal(str)
def __init__(self):
super(DemoCode, self).__init__()
self.setupUi(self)
self.pushButton.clicked.connect(self.button_clicked)
self.signal.connect(self.label.setText)
def button_clicked(self):
threading.Thread(
target=callingexternalfunction, args=(self.signal,), daemon=True
).start()
if __name__ == "__main__":
import sys
app = QtWidgets.QApplication(sys.argv)
window = DemoCode()
window.show()
sys.exit(app.exec_())
callingexternalfunction.py
import time
def callingexternalfunction(signal):
for i in range(0,5):
time.sleep(3)
signal.emit('3 Second Pause '+ str(i))