我正在使用天气应用程序,但是在使代码变干时遇到了一些麻烦。当我使用许多DOM方法时就会发生这种情况。这是一些代码:
if(document.querySelector('.container').contains(document.querySelector('.results__container'))
&& document.querySelector('.container').contains(document.querySelector('.results__weather--temperature'))
&& document.querySelector('.container').contains(document.querySelector('.city__name')))
{
document.querySelector('.container').removeChild(document.querySelector('.results__container'));
document.querySelector('.container').removeChild(document.querySelector('.results__weather--temperature'));
document.querySelector('.container').removeChild(document.querySelector('.city__name'));
}
这里还有更多:
if(weather.main === 'Haze' || weather.main === 'Mist' || weather.main === 'Smoke')
{
//remove css of previous city's weather
document.querySelector('.container').className = 'container';
document.querySelector('.mist__container--outer').classList.remove('appear');
document.querySelector('.cloud__container').classList.remove('appear');/
document.querySelector('.sun').classList.remove('appear');
//add css of new city's weather
document.querySelector('.container').classList.add('background__mist');
document.querySelector('.mist__container--outer').classList.add('appear');
}
检索在多个位置使用的DOM元素,并将它们存储在变量中,以供以后参考:
let c = document.querySelector('.container')
let rc = document.querySelector('.results__container')
let wt = document.querySelector('.results__weather--temperature')
let cn = document.querySelector('.city__name')
if(c.contains(rc)
&& c.contains(wt)
&& c.contains(cn))
{
c.removeChild(rc);
c.removeChild(wt);
c.removeChild(cn);
}