[具有分析功能的sql查询的jooq查询

Question

我有类似SQL的查询

select *
from (
   select s.*, max(year) over () max_year
   from Transaction s
   where s.Account_Number     = '4234242234'
     and s.month in (0,1)) o
where o.year=o.max_year;

我需要用jOOQ编写任何帮助。我尝试了以下

dslContext.select(Transaction.BANK,
                    Transaction.ACCOUNT,
                    Transaction.AMOUNT,
                    max(Transaction.YEAR).over())
            .from(Transaction)
            .where(Transaction.BANK.eq(bank))
            .and(Transaction.MONTH.in((byte) 0, (byte) 1))
            .fetchInto(Transaction.class);

此外，有什么方法可以避免列出select中的所有列。代替

select(Transaction.BANK,
       Transaction.ACCOUNT,
       Transaction.AMOUNT,
       max(Transaction.YEAR).over())

类似

select(Transaction.*,
       max(Transaction.YEAR).over())

Answer 1

派生表可以这样构造：

// Assuming this static import, as always:
import static org.jooq.impl.DSL.*;

// Create aliased column expression for later reuse
Field<Integer> maxYear = max(Transaction.YEAR).over().as("max_year");

// Create derived table
Table<?> o = select(Transaction.asterisk(), maxYear)
            .from(Transaction)
            .where(Transaction.BANK.eq(bank))
            .and(Transaction.MONTH.in((byte) 0, (byte) 1));

// Use derived table and dereference fields from it using Table.field(Field)
ctx.select()
   .from(o)
   .where(o.field(Transaction.YEAR).eq(o.field(maxYear)))
   .fetch();

还有，有什么方法可以避免列出select中的所有列？>

您正在寻找Table.asterisk()以在SQL中产生星号，或Table.asterisk()以从所生成的代码产生所有字段。