我正在尝试匹配以下数据，以便可以提取时间码之间的文本。
subs='''
1
00:00:00,130 --> 00:00:01,640
where you there when it
happened?
Who else saw you?
2
00:00:01,640 --> 00:00:03,414
This might be your last chance to
come clean. Take it or leave it.
'''
Regex=re.compile(r'(\d\d:\d\d\:\d\d,\d\d\d) --> (\d\d:\d\d\:\d\d,\d\d\d)(\n.+)((\n)?).+')
我的正则表达式与时间码的第一行和文本的第一行匹配，但仅从第二行而不是整个第二行返回几个字符。如何获取匹配超时代码和实时代码之间的所有内容？
我不确定，但是我认为以下解决方案更适合您的情况...※使用下面的解决方案，您不仅可以提取时间码之间的文本，还可以将文本连接到时间码。
import re
multiline_text=\
"""
1 00:00:00,130 --> 00:00:01,640
where you there when it happened?
Who else saw you?
2 00:00:01,640 --> 00:00:03,414
This might be your last chance to
come clean. Take it or leave it.
"""
lines = multiline_text.split('\n')
dict = {}
current_key = None;
for line in lines:
is_key_match_obj = re.search('([\d\:\,]{12})(\s-->\s)([\d\:\,]{12})', line)
if is_key_match_obj:
current_key = is_key_match_obj.group()
continue
if current_key:
if current_key in dict:
if not line:
dict[current_key] += '\n'
else:
dict[current_key] += line
else:
dict[current_key] = line
print(dict)
当前方法的一个可能的问题是，尝试捕获时间戳之间的所有内容时，您没有使用DOT ALL模式。我有re.search在DOT ALL模式下工作：
subs="""
1 00:00:00,130 --> 00:00:01,640
where you there when it happened?
Who else saw you?
2 00:00:01,640 --> 00:00:03,414
This might be your last chance to
come clean. Take it or leave it. """
match = re.search(r'\d+ \d{2}:\d{2}:\d{2},\d+ --> \d{2}:\d{2}:\d{2},\d+\s*(.*)\d+ \d{2}:\d{2}:\d{2},\d+ --> \d{2}:\d{2}:\d{2},\d+', subs, flags=re.DOTALL)
if match:
print match.group(1)
else:
print 'NO MATCH'
此打印：
where you there when it happened?
Who else saw you?
您也可以不使用DOTALL而获得比赛。
匹配时间码并在组1中捕获，使用负前瞻将不以时间码开头的以下所有行与之匹配。
^\d{2}:\d{2}:\d{2},\d+ --> \d{2}:\d{2}:\d{2},\d+((?:\r?\n(?!\d{2}:\d{2}:\d{2},\d+ --> \d{2}:\d{2}:\d{2},\d).*)*)
部分
^字符串的开头\d{2}:\d{2}:\d{2},\d+ --> \d{2}:\d{2}:\d{2},\d+匹配时间码模式(捕获组1(?:非捕获组\r?\n匹配新人(?!\d{2}:\d{2}:\d{2},\d+ --> \d{2}:\d{2}:\d{2},\d)负前瞻，不声明时间码.*匹配除换行符0+次以外的任何字符)*关闭非捕获组并重复0+次])关闭捕获组1