如何反转Newtonsoft JsonConvert PopulateObject

Question

如何区分对象的2个版本的2个Json表示形式，以便可以将输出提供给JsonConvert.PopulateObject（...）以将对象的第一个版本转换为第二个版本。例如：

public class Dog
{
  public string Name { get; set; }
  public int Age { get; set; }
}

var myDog = new Dog { Name = "Dio", Age = 1 };

var before = JsonConvert.SerializeObject(myDog); // { "Name": "Dio", "Age" : 1 }

myDog.Age++;

var after = JsonConvert.SerializeObject(myDog);   // { "Name": "Dio", "Age" : 2 }

// How do I generate this variable, so that I can use it with PopulateObject?
var ageIncrementJson = "{ \"Age\" : 2 }";

myDog = new Dog { Name = "Dio", Age = 1 };

JsonConvert.PopulateObject(ageIncrementJson, myDog);

// myDog should now have an age of 2

[我已经尝试过使用JsonDiffPatch，但是会产生前后文件，但Newtonsoft不接受（例如{“ Age”：[“ 1”，“ 2”]}

）

Answer 1

public class Dog
{
    public string Name { get; set; }
    public int Age { get; set; }
}

public static void Test()
{
    var myDog = new Dog { Name = "Dio", Age = 1 };

    var before = JsonConvert.SerializeObject(myDog); // { "Name": "Dio", "Age" : 1 }

    myDog.Age++;

    var after = JsonConvert.SerializeObject(myDog);   // { "Name": "Dio", "Age" : 2 }

    // How do I generate this variable, so that I can use it with PopulateObject?
    var ageIncrementJson = "{ \"Age\" : 2 }";

    var diffJson = GetDiffJson(JsonConvert.DeserializeObject<Dog>(before)
            , JsonConvert.DeserializeObject<Dog>(after));

    myDog = new Dog { Name = "Dio", Age = 1 };

    JsonConvert.PopulateObject(ageIncrementJson, myDog);

    // myDog should now have an age of 2
}

private static string GetDiffJson(Dog d1, Dog newDog)
{
    var dic = new Dictionary<string, object>();

    // alternatively use reflection, for each property...
    if (d1.Age != newDog.Age)
        dic[nameof(d1.Age)] = newDog.Age;

    if (d1.Name != newDog.Name)
        dic[nameof(d1.Name)] = newDog.Name;

    return JsonConvert.SerializeObject(dic);
}