我正在尝试编写一个函数来向K和M提供数千和数百万例如:
1000 = 1k
1100 = 1.1k
15000 = 15k
115000 = 115k
1000000 = 1m
这是我到目前为止的地方:
func formatPoints(num: Int) -> String {
let newNum = String(num / 1000)
var newNumString = "\(num)"
if num > 1000 && num < 1000000 {
newNumString = "\(newNum)k"
} else if num > 1000000 {
newNumString = "\(newNum)m"
}
return newNumString
}
formatPoints(51100) // THIS RETURNS 51K instead of 51.1K
如何让这个功能起作用,我缺少什么?
func formatPoints(num: Double) ->String{
let thousandNum = num/1000
let millionNum = num/1000000
if num >= 1000 && num < 1000000{
if(floor(thousandNum) == thousandNum){
return("\(Int(thousandNum))k")
}
return("\(thousandNum.roundToPlaces(1))k")
}
if num > 1000000{
if(floor(millionNum) == millionNum){
return("\(Int(thousandNum))k")
}
return ("\(millionNum.roundToPlaces(1))M")
}
else{
if(floor(num) == num){
return ("\(Int(num))")
}
return ("\(num)")
}
}
extension Double {
/// Rounds the double to decimal places value
func roundToPlaces(places:Int) -> Double {
let divisor = pow(10.0, Double(places))
return round(self * divisor) / divisor
}
}
如果数字是完整的,更新的代码现在应该不返回.0。现在应该输出1k而不是1.0k。我只是检查了双倍和它的地板是否相同。
我在这个问题中找到了双重扩展:Rounding a double value to x number of decimal places in swift
以下扩展如下 -
.0
小数)。extension Double {
var kmFormatted: String {
if self >= 10000, self <= 999999 {
return String(format: "%.1fK", locale: Locale.current,self/1000).replacingOccurrences(of: ".0", with: "")
}
if self > 999999 {
return String(format: "%.1fM", locale: Locale.current,self/1000000).replacingOccurrences(of: ".0", with: "")
}
return String(format: "%.0f", locale: Locale.current,self)
}
}
用法:
let num: Double = 1000001.00 //this should be a Double since the extension is on Double
let millionStr = num.kmFormatted
print(millionStr)
打印1M
在这里,它正在行动 -
extension Int {
var roundedWithAbbreviations: String {
let number = Double(self)
let thousand = number / 1000
let million = number / 1000000
if million >= 1.0 {
return "\(round(million*10)/10)M"
}
else if thousand >= 1.0 {
return "\(round(thousand*10)/10)K"
}
else {
return "\(self)"
}
}
}
print(11.roundedWithAbbreviations) // "11"
print(11111.roundedWithAbbreviations) // "11.1K"
print(11111111.roundedWithAbbreviations) // "11.1 M"
答案中的一些变化(对于Int和正确的百万):
func formatPoints(num: Int) ->String{
let thousandNum = num/1000
let millionNum = num/1000000
if num >= 1000 && num < 1000000{
if(thousandNum == thousandNum){
return("\(thousandNum)k")
}
return("\(thousandNum)k")
}
if num > 1000000{
if(millionNum == millionNum){
return("\(millionNum)M")
}
return ("\(millionNum)M")
}
else{
if(num == num){
return ("\(num)")
}
return ("\(num)")
}
}
Swift 3中的上述解决方案(来自@qlear):
func formatPoints(num: Double) -> String {
var thousandNum = num / 1_000
var millionNum = num / 1_000_000
if num >= 1_000 && num < 1_000_000 {
if floor(thousandNum) == thousandNum {
return("\(Int(thousandNum))k")
}
return("\(thousandNum.roundToPlaces(1))k")
}
if num > 1_000_000 {
if floor(millionNum) == millionNum {
return "\(Int(thousandNum))k"
}
return "\(millionNum.roundToPlaces(1))M"
}
else{
if floor(num) == num {
return "\(Int(num))"
}
return "\(num)"
}
}
extension Double {
// Rounds the double to decimal places value
mutating func roundToPlaces(_ places : Int) -> Double {
let divisor = pow(10.0, Double(places))
return (self.rounded() * divisor) / divisor
}
}
对于swift 4.0。它的工作完全正常,并根据@ user3483203回答
将Double值转换为String的函数
func formatPoints(num: Double) ->String{
var thousandNum = num/1000
var millionNum = num/1000000
if num >= 1000 && num < 1000000{
if(floor(thousandNum) == thousandNum){
return("\(Int(thousandNum))k")
}
return("\(thousandNum.roundToPlaces(places: 1))k")
}
if num > 1000000{
if(floor(millionNum) == millionNum){
return("\(Int(thousandNum))k")
}
return ("\(millionNum.roundToPlaces(places: 1))M")
}
else{
if(floor(num) == num){
return ("\(Int(num))")
}
return ("\(num)")
}
}
进行一次Double扩展
extension Double {
/// Rounds the double to decimal places value
mutating func roundToPlaces(places:Int) -> Double {
let divisor = pow(10.0, Double(places))
return Darwin.round(self * divisor) / divisor
}
}
使用上述功能
UILABEL.text = formatPoints(num:Double(310940)!)
输出:
要添加答案,这里是一个Swift 4.X版本,使用循环可以在必要时轻松添加/删除单位:
extension Double {
var shortStringRepresentation: String {
if self.isNaN {
return "NaN"
}
if self.isInfinite {
return "\(self < 0.0 ? "-" : "+")Infinity"
}
let units = ["", "k", "M"]
var interval = self
var i = 0
while i < units.count - 1 {
if abs(interval) < 1000.0 {
break
}
i += 1
interval /= 1000.0
}
// + 2 to have one digit after the comma, + 1 to not have any.
// Remove the * and the number of digits argument to display all the digits after the comma.
return "\(String(format: "%0.*g", Int(log10(abs(interval))) + 2, interval))\(units[i])"
}
}
例子:
$ [1.5, 15, 1000, 1470, 1000000, 1530000, 1791200000].map { $0.shortStringRepresentation }
[String] = 7 values {
[0] = "1.5"
[1] = "15"
[2] = "1k"
[3] = "1.5k"
[4] = "1M"
[5] = "1.5M"
[6] = "1791.2M"
}
基于@qlear的解决方案。 我注意到如果数字正好是1000000,它将返回1000000未格式化。 所以我把它添加到函数中。我还包括负值..因为不是每个人都在赚钱!
func formatPoints(num: Double) ->String{
let thousandNum = num/1000
let millionNum = num/1000000
if num > 0
{
if num >= 1000 && num < 1000000{
if(floor(thousandNum) == thousandNum){
return("\(Int(thousandNum))k")
}
return("\(round1(thousandNum, toNearest: 0.01))k")
}
if num > 1000000{
if(floor(millionNum) == millionNum){
return("\(Int(thousandNum))k")
}
return ("\(round1(millionNum, toNearest: 0.01))M")
}
else if num == 1000000
{
return ("\(round1(millionNum, toNearest: 0.01))M")
}
else{
if(floor(num) == num){
return ("\(Int(num))")
}
return ("\(round1(num, toNearest: 0.01))")
}
}
else
{
if num <= -1000 && num > -1000000{
if(floor(thousandNum) == thousandNum){
return("\(Int(thousandNum))k")
}
return("\(round1(thousandNum, toNearest: 0.01))k")
}
if num < -1000000{
if(floor(millionNum) == millionNum){
return("\(Int(thousandNum))k")
}
return ("\(round1(millionNum, toNearest: 0.01))M")
}
else if num == -1000000
{
return ("\(round1(millionNum, toNearest: 0.01))M")
}
else{
if(floor(num) == num){
return ("\(Int(num))")
}
return ("\(round1(num, toNearest: 0.01))")
}
}
}
当然是数字扩展:
extension Double {
/// Rounds the double to decimal places value
func round1(_ value: Double, toNearest: Double) -> Double {
return Darwin.round(value / toNearest) * toNearest
}
}
对@chrisz答案的轻微改进,Swift-4 Doble extension
- 在所有情况下都可以正常工作。
extension Double {
// Formatting double value to k and M
// 1000 = 1k
// 1100 = 1.1k
// 15000 = 15k
// 115000 = 115k
// 1000000 = 1m
func formatPoints() -> String{
let thousandNum = self/1000
let millionNum = self/1000000
if self >= 1000 && self < 1000000{
if(floor(thousandNum) == thousandNum){
return ("\(Int(thousandNum))k").replacingOccurrences(of: ".0", with: "")
}
return("\(thousandNum.roundTo(places: 1))k").replacingOccurrences(of: ".0", with: "")
}
if self > 1000000{
if(floor(millionNum) == millionNum){
return("\(Int(thousandNum))k").replacingOccurrences(of: ".0", with: "")
}
return ("\(millionNum.roundTo(places: 1))M").replacingOccurrences(of: ".0", with: "")
}
else{
if(floor(self) == self){
return ("\(Int(self))")
}
return ("\(self)")
}
}
/// Returns rounded value for passed places
///
/// - parameter places: Pass number of digit for rounded value off after decimal
///
/// - returns: Returns rounded value with passed places
func roundTo(places:Int) -> Double {
let divisor = pow(10.0, Double(places))
return (self * divisor).rounded() / divisor
}
}