我需要在Kotlin中将UNIX时间戳转换为ByteArray
。问题是,当我使用下面的代码执行此操作时,我得到的结果类似于C1F38E05
(hex),它高于当前的纪元时间。
internal fun Int.toByteArray(): ByteArray {
return byteArrayOf(
this.ushr(24).toByte(),
this.ushr(16).toByte(),
this.ushr(8).toByte(),
this.toByte()
)
}
val timeUTC = System.currentTimeMillis().toInt().toByteArray()
做正确的方法是什么?
如果需要32位值,则需要将时间转换为秒。
fun Int.toByteArray() = byteArrayOf(
this.toByte(),
(this ushr 8).toByte(),
(this ushr 16).toByte(),
(this ushr 24).toByte()
)
val timeUTC = (System.currentTimeMillis() / 1000).toInt().toByteArray()
System.currentTimeMillis()
返回Long
所以toByteArray
必须像Long
一样实现:
fun Long.toByteArray(): ByteArray {
val result = ByteArray(8)
result[7] = (this and 0xFF).toByte()
result[6] = ((this ushr 8) and 0xFF).toByte()
result[5] = ((this ushr 16) and 0xFF).toByte()
result[4] = ((this ushr 24) and 0xFF).toByte()
result[3] = ((this ushr 32) and 0xFF).toByte()
result[2] = ((this ushr 40) and 0xFF).toByte()
result[1] = ((this ushr 48) and 0xFF).toByte()
result[0] = ((this ushr 56) and 0xFF).toByte()
return result
}
如果你需要这个用于无符号字节,请使用:
fun Long.toByteArray(): UByteArray {
val result = UByteArray(8)
result[7] = (this and 0xFF).toUByte()
result[6] = ((this ushr 8) and 0xFF).toUByte()
result[5] = ((this ushr 16) and 0xFF).toUByte()
result[4] = ((this ushr 24) and 0xFF).toUByte()
result[3] = ((this ushr 32) and 0xFF).toUByte()
result[2] = ((this ushr 40) and 0xFF).toUByte()
result[1] = ((this ushr 48) and 0xFF).toUByte()
result[0] = ((this ushr 56) and 0xFF).toUByte()
return result
}
这可以像下面的示例一样使用:
fun main() {
val timeUTC = System.currentTimeMillis().toByteArray()
println(timeUTC.map { byte -> byte.toString(16).toUpperCase() }.joinToString(""))
}