可运行处理程序未在片段内执行。无法启动一个可运行的

Question

我在一个fragment里面有一个Runnable，这个Runnable是用来更新textviews以及使用按钮接收输入的。runnable的作用是更新文本视图以及使用按钮接收输入。但是程序在runnable里面一次也没有输入。

请大家帮忙。我到底做错了什么！谢谢！代码如下。我在runnable里面有按钮和textviews。

public class TodayFragment extends Fragment {
//initialisations

@Override
public View onCreateView(LayoutInflater inflater, ViewGroup container,
                             Bundle savedInstanceState) {

//UI initialisations

Handler mHandler = new Handler();
Runnable mTicker = new Runnable() {
            @Override
            public void run() {

//user interface interactions and updates on screen

    mHandler.postDelayed(mTicker, 1000);


   mTicker.run();

 }

Answer 1

试试这个变化

mTicker = new Runnable() {
        public void run() {

         //user interface interactions and updates on screen

           mHandler.postDelayed(mTicker, 1000);

        }
    };
    mTicker.run();

Answer 2

似乎你想每隔一秒就改变你的视图。如果你这么说，你应该在你的runnable方法之外执行你的处理程序。

    Handler mHandler = new Handler();
    Runnable mTicker = new Runnable() {
        @Override
        public void run() {

            // user interface interactions and updates on screen
            // if you want to run this handler only once then delete below line
            mHandler.postDelayed(mTicker, 1000);

        }
    };

mHandler.postDelayed(mTicker, 1000);

Answer 3

这对我来说是可行的

public class TodayFragment extends Fragment {
//initialisations
Runnable mTicker;

@Override
public View onCreateView(LayoutInflater inflater, ViewGroup container,
                         Bundle savedInstanceState) {

    final Handler mHandler = new Handler();
    mTicker = new Runnable() {
        @Override
        public void run() {

            // user interface interactions and updates on screen

            mHandler.postDelayed(mTicker, 1000);

            }
        };

    mHandler.postDelayed(mTicker, 1000);

    return inflater.inflate(R.layout.fragment_today, container, false);;

}