GLFW 错误#65544“无法初始化 GLFW”

Question

这是我的代码：

#include <iostream>
#include <GLFW/glfw3.h>

int main(void){

    GLFWwindow* window;

    if(!glfwInit()){
        std::cout << "Failed to initialize GLFW!" << std::endl;
        return -1;
    }

    window = glfwCreateWindow(640, 480, "Hello World", NULL, NULL);
    if(!window){
        glfwTerminate();
        std:: cout << "Failed to initialize Window!" << std::endl;
        return -1;
    }

    glfwMakeContextCurrent(window);

    while(!glfwWindowShouldClose(window)){
        glClear(GL_COLOR_BUFFER_BIT);

        glfwSwapBuffers(window);

        glfwPollEvents();
    }
    glfwTerminate();
    return 0;
}

我成功地链接并编译了它，但是我遇到了运行时错误 它说 glfw 初始化失败。我试图在 C 中使用 glfw 但这个错误显示

Wayland: Failed to connect to display
The GLFW library is not initialized
main: ./src/posix_thread.c:64: _glfwPlatformGetTls: Assertion `tls->posix.allocated == GLFW_TRUE' failed.
Aborted (core dumped)

.我正在使用 popOS 22.04 LTS，我是 c++ 的新手，glfw 请帮我解决这个问题

Answer 1

问题

您收到这些错误的原因是因为 glfw 框架在用于创建窗口之前没有机会进行初始化。因此，glfw 返回给定的错误消息。

Wayland: Failed to connect to display
The GLFW library is not initialized
main: ./src/posix_thread.c:64: _glfwPlatformGetTls: Assertion `tls-posix.allocated == GLFW_TRUE' failed.
Aborted (core dumped)

解决方案

要解决此问题，请尝试移动代码段

if(!glfwInit()){
    std::cout << "Failed to initialize GLFW!" << std::endl;
    return -1;
}

在main函数开头的

GLFWwindow* window

声明之上

快速提示

尝试像这样在一行中声明和初始化窗口：

GLFWwindow* window = glfwCreateWindow(WIDTH, HEIGHT, "GLFW WINDOW", NULL, NULL)

它更容易阅读，总体上有助于减少代码行数。