我有一个使用 React-Router 创建的导航
nav.tsx
import React from 'react'
import { menu } from './menu'
import { Link } from 'react-router-dom'
import styles from './HamburgerMenu.module.scss'
const HamburgerMenu: React.FC = () => {
const [active, setActive] = React.useState<number>(0)
console.log(active)
return (
<nav>
<ul className={styles.menu}>
{menu.map((item, index) => (
<li
onClick={() => setActive(index)}
key={item.title}
className={styles[active === index ? 'active' : '']}
>
<Link to={item.link}>{item.title}</Link>
</li>
))}
</ul>
</nav>
)
}
export default HamburgerMenu
菜单.ts:
export const menu: IMenuItem[] = [
{
link: '/',
title: 'главная'
},
{
link: '/profile',
title: 'профиль'
},
{
link: '/discipline',
title: 'наказания'
},
{
link: '/store',
title: 'магазин'
},
{
link: '/statistics',
title: 'статистика'
}
]
main.tsx:
import React from 'react'
import ReactDOM from 'react-dom/client'
import { RouterProvider, createBrowserRouter } from 'react-router-dom'
import Home from './pages/Home/Home'
import './assets/style/global.scss'
import NotFoundPage from './pages/NotFoundPage'
import Profile from './pages/Profile/Profile'
const router = createBrowserRouter([
{
element: <Home />,
path: '/'
},
{
element: <Profile />,
path: '/profile'
},
{
element: <NotFoundPage />,
path: '*'
}
])
ReactDOM.createRoot(document.getElementById('root')!).render(
<React.StrictMode>
<RouterProvider router={router} />
</React.StrictMode>
)
当在
'/'
和'/profile'
之间切换时,"active"
类不断重置并切换为0,如果我想要将"active"
类添加到'/profile'
,那么我需要点击它2次,如果我在 '/discipline'
、'/store'
、'/statistics'
之间切换,则可以正常分配班级。我知道这种行为很可能是由于 '/discipline'
、'/store'
、'/statistics'
不是声明页面,但是 '/'
和 '/profile'
又如何呢?为什么会发生这种情况,如何纠正?
使用
NavLink
组件,默认为匹配的链接应用 "active"
类名,并使用 CSS 选择具有当前匹配链接的 li
元素。
示例:
const HamburgerMenu: React.FC = () => {
return (
<nav>
<ul className={styles.menu}>
{menu.map((item, index) => (
<li
key={item.title}
className="nav-link-item" // <-- something easily targetable
>
<NavLink end to={item.link}>
{item.title}
</NavLink>
</li>
))}
</ul>
</nav>
);
};
li.nav-link-item {
/* li styling */
}
li.nav-link-item:has(a.active) {
/* "active" li styling overrides */
}
信息: