使用Python访问Json变量时出现cx_Oracle错误

问题描述 投票:0回答:1

我是Python新手,我很难得到Json变量。

payload = ""
headers = {
    'Authorization': authorization,
    'cache-control': "no-cache",
    'Postman-Token': "65a104eb-1210-4eeb-880b-ceed78b21364"
    }

response = requests.request("GET", url, data=payload, headers=headers)

x = json.loads(response.text, object_hook=lambda d: namedtuple('X',    
    d.keys())(*d.values()))

for a in x:
    print(a.numeroComlink)

connection = cx_Oracle.connect('xxxxx/xxxxx@XE')
cursor = connection.cursor()
sql_insert = "insert into usu_obt_cot (usu_numclk) values (:usu_numclk)"
cursor.execute(sql_insert, {"usu_numclk": int(x.numeroComlink)})

connection.commit()
cursor.close()

正如您在上面的代码中所看到的,我在代码中间有一个打印引用了下面所说的错误没有属性的确切字段。

Error Received

从现在起,我很感激你的关注。

python json oracle cx-oracle
1个回答
0
投票

Cursor.execute只会执行一个insert语句,而x中有很多值。如果你想让它插入list“x”中的所有值,你可以在一个循环中做一堆单个插入语句(这很简单,但可能不会表现得非常好)......

...
sql_insert = "insert into usu_obt_cot (usu_numclk) values (:usu_numclk)"
for a in x:
    cursor.execute(sql_insert, {"usu_numclk": int(a.numeroComlink)})
...

或者你可以follow the examples in this similar question并尝试使用Cursor.executeMany进行批量插入。

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