我的目标是从空格中删除下标或上标格式。
当我运行下面的代码时,只有top函数有效,而lower函数无法执行任何操作。如果我切换功能的位置,仍然只有顶部功能工作。功能几乎完全相同,我不知道从哪里开始修复它。请有人指出我正确的方向吗?
Dim oRng As Word.Range
Set oRng = ActiveDocument.Range
'For subscripted spaces
Selection.HomeKey unit:=wdStory
With oRng.Find
.ClearFormatting
.Replacement.ClearFormatting
.Forward = True
.Text = "[A-z0-9] "
.Replacement.Text = ""
.MatchWholeWord = False
While .Execute
If oRng.Characters(2).Font.Subscript = True Then
oRng.Characters(2).Font.Subscript = False
End If
oRng.Collapse direction:=wdCollapseEnd
Wend
End With
'For superscripted spaces
Selection.HomeKey unit:=wdStory
With oRng.Find
.ClearFormatting
.Replacement.ClearFormatting
.Forward = True
.Text = "[A-z0-9] "
.Replacement.Text = ""
.MatchWholeWord = False
While .Execute
If oRng.Characters(2).Font.Superscript = True Then
oRng.Characters(2).Font.Superscript = False
End If
oRng.Collapse direction:=wdCollapseEnd
Wend
End With
问题是,当您完成处理首先放置的系列时,Rng定义的范围已折叠到最后一个Found实例。无论如何,你不需要循环。尝试:
Sub Demo()
Application.ScreenUpdating = False
With ActiveDocument.Range
With .Find
.ClearFormatting
.Replacement.ClearFormatting
.Text = " "
.Replacement.Text = "^&"
.Forward = True
.Wrap = wdFindContinue
.Format = True
.Font.Superscript = True
.Replacement.Font.Superscript = False
.Execute Replace:=wdReplaceAll
.Font.Subscript = True
.Replacement.Font.Subscript = False
.Execute Replace:=wdReplaceAll
End With
End With
Application.ScreenUpdating = True
End Sub