我已经改变了我从my original question的方法来改造整个类,并把它放在一个可变元组中。我现在可以按照我希望它们的创建方式使用getter和setter。但是,现在我试图向前迈出一步,将各个控制器组合成一个控制器。
#ifndef CONTROLLER_HPP
#define CONTROLLER_HPP
#include <functional>
#include <vector>
#include <iostream>
#include <utility>
template<typename...Classes>
class Controller
{
public:
Controller(Classes&...objects) : objects(objects...){}
void setValues(int value)
{
std::apply([&](auto&...x) { (x.updateValue(value),...);}, objects);
}
void getValues(std::vector<int> &values)
{
std::apply([&](auto&...x) { (values.push_back(x.get()),...);}, objects);
}
private:
std::tuple<Classes&...> objects;
};
#endif
有了这个我可以做到以下几点:
classA A;
classB B;
classC C;
classD D;
classE E;
classF F;
classG G;
Controller controller1(A,B,C);
Controller controller2(D,E);
Controller controller3(F,G);
controller1.setValues(20);
controller2.setValues(13);
controlelr3.setValues(32);
但是,我想更进一步,将两者结合起来:
Controller master(controller1,controller2,controller3);
master.setValues(40);
我看过at this post talking about joining variadic templates,但我认为这会返回一个类型(?)而不是类。我也试过创建两个重载类,但我不认为我正在创建正确的重载:
template<typename...Classes>
class Controller
{
public:
Controller(Classes&...objects) : objects(objects...){}
void setValues(int value)
{
std::apply([&](auto&...x) { (x.updateValue(value),...);}, objects);
}
void getValues(std::vector<int> &values)
{
std::apply([&](auto&...x) { (values.push_back(x.get()),...);}, objects);
}
private:
std::tuple<Classes&...> objects;
};
template<Controller<typename ... > class Controllers, typename ...Classes>
class Controller<Controllers<Classes&...classes>...>
{
// create a new controller that takes all the combined classes
};
如何将任意数量的模板化可变参数模板类组合成一个类?我确实有能力使用C ++ 17。
template<typename...Classes>
class Controller
{
Controller( std::tuple<Classes&...> tup ):objects(tup) {}
public:
template<class...Rhs>
Controller<Classes..., Rhs...> operator+( Controller<Rhs...> rhs ) const {
return std::tuple_cat( objects, rhs.objects );
}
...
给我们:
Controller master = controller1+controller2+controller3;
master.setValues(40);