我有字符串:
text = '''TextTextTextTextTextTextTextTextText1
TextTextTextTextTextTextTextTextText1
TextTextTextTextTextTextTextTextText2
TextTextTextTextTextTextTextTextText2
TextTextTextTextTextTextTextTextText2
TextTextTextTextTextTextTextTextText2
TextTextTextTextTextTextTextTextText2
TextTextTextTextTextTextTextTextText3
TextTextTextTextTextTextTextTextText3
TextTextTextTextTextTextTextTextText3
TextTextTextTextTextTextTextTextText4
TextTextTextTextTextTextTextTextText4
TextTextTextTextTextTextTextTextText4'''
我想通过缩进分割此字符串并将其添加到列表中。这是我当前的代码:
nr_lines = 0
indent_dict = {}
for line in summary1.splitlines(True):
print(line)
print("------------------------------")
nr_lines+=1
whitespaces_count = len(line) - len(line.lstrip())
indent_dict[nr_lines] = whitespaces_count
print(indent_dict)
list_of_values = []
# Removed first key with value (indent) = 0
indent_dict_without = dict(indent_dict)
key = 1
del indent_dict_without[key]
# Adding values from dict to list
for key, value in indent_dict_without.items():
list_of_values.append(value)
print(list_of_values)
# Finding minimum value
x = min(list_of_values)
list_of_small = []
for nr in list_of_values:
if nr == x:
list_of_small.append(nr)
print(list_of_small)
# Finding which line have all smallest indent
n = 0
key_1 = []
for key, value in indent_dict.items():
if value == list_of_small[n]:
key_1.append(key)
print(key_1)
输出为:
{1: 0, 2: 12, 3: 8, 4: 12, 5: 12, 6: 12, 7: 12, 8: 8, 9: 12, 10: 12, 11: 8, 12: 12, 13: 12} # dict with line and value (indent)
[12, 8, 12, 12, 12, 12, 8, 12, 12, 8, 12, 12] # list with indents
[8, 8, 8] # the smallest indents
[3, 8, 11] # lines for smallest indents
现在,我不知道如何拆分和添加这4个部分作为列表的元素:
list = ['TextTextTextTextTextTextTextTextText1
TextTextTextTextTextTextTextTextText1',
'TextTextTextTextTextTextTextTextText2
TextTextTextTextTextTextTextTextText2
TextTextTextTextTextTextTextTextText2
TextTextTextTextTextTextTextTextText2
TextTextTextTextTextTextTextTextText2',
'TextTextTextTextTextTextTextTextText3
TextTextTextTextTextTextTextTextText3
TextTextTextTextTextTextTextTextText3',
'TextTextTextTextTextTextTextTextText4
TextTextTextTextTextTextTextTextText4
TextTextTextTextTextTextTextTextText4']
我应该创建一个新变量并逐行添加行,直到新缩进吗?
这是我最快想到的。我敢肯定还有更优雅的解决方案
text = '''TextTextTextTextTextTextTextTextText1
TextTextTextTextTextTextTextTextText1
TextTextTextTextTextTextTextTextText2
TextTextTextTextTextTextTextTextText2
TextTextTextTextTextTextTextTextText2
TextTextTextTextTextTextTextTextText2
TextTextTextTextTextTextTextTextText2
TextTextTextTextTextTextTextTextText3
TextTextTextTextTextTextTextTextText3
TextTextTextTextTextTextTextTextText3
TextTextTextTextTextTextTextTextText4
TextTextTextTextTextTextTextTextText4
TextTextTextTextTextTextTextTextText4'''
lines = text.split('\n')
# Count spaces in each line
indent_lst = [line.count(' ') for line in text.splitlines(True)]
# Find where indentation changes
indices = []
for idx in range(len(indent_lst[1:])): # Start at second element in list
# Here I assume, that the indentation is constant. A change from more spaces to fewer spaces means,
# that a new block has started
if indent_lst[idx-1] > indent_lst[idx]: # Look back at previous element and compare with current
indices.append(idx)
final_lst = []
# Use slicing to append from block to block
for idx in range(len(indices)):
if indices.index(indices[idx]) == (len(indices) -1 ): # Take care of last block
final_lst.append(''.join(lines[indices[idx]:]))
else:
final_lst.append(''.join(lines[indices[idx]:indices[idx+1]])) # Add block to final list
print(final_lst)
这里是结果:
['TextTextTextTextTextTextTextTextText1 TextTextTextTextTextTextTextTextText1', ' TextTextTextTextTextTextTextTextText2 TextTextTextTextTextTextTextTextText2 TextTextTextTextTextTextTextTextText2 TextTextTextTextTextTextTextTextText2 TextTextTextTextTextTextTextTextText2', ' TextTextTextTextTextTextTextTextText3 TextTextTextTextTextTextTextTextText3 TextTextTextTextTextTextTextTextText3', ' TextTextTextTextTextTextTextTextText4 TextTextTextTextTextTextTextTextText4 TextTextTextTextTextTextTextTextText4']
我希望这已经对您有所帮助,并随时询问您是否有问题!
如果我对您的理解正确,您希望找到所有缩进最小的行。
我处理此问题的方法如下。我将创建一个defaultdict,将组成缩进的空格的数字作为键,并将包含该缩进的行的所有索引的列表作为值,作为一个值:
from collections import defaultdict
text = '''TextTextTextTextTextTextTextTextText1
TextTextTextTextTextTextTextTextText1
TextTextTextTextTextTextTextTextText2
TextTextTextTextTextTextTextTextText2
TextTextTextTextTextTextTextTextText2
TextTextTextTextTextTextTextTextText2
TextTextTextTextTextTextTextTextText2
TextTextTextTextTextTextTextTextText3
TextTextTextTextTextTextTextTextText3
TextTextTextTextTextTextTextTextText3
TextTextTextTextTextTextTextTextText4
TextTextTextTextTextTextTextTextText4
TextTextTextTextTextTextTextTextText4'''
def count_indentation(line):
return len(line) - len(line.lstrip())
lines = text.splitlines(keepends=False)
indent_dict = defaultdict(list)
for idx, line in enumerate(lines):
if count_indentation(line) > 0:
indent_dict[count_indentation(line)].append(idx)
现在indent_dict
看起来像:
defaultdict(list, {8: [1, 3, 4, 5, 6, 8, 9, 11, 12], 4: [2, 7, 10]})
接下来,我们用最小的键找到相关行的索引:
smallest_indent = min(indent_dict)
line_idexes_smalles_indents = indent_dict[smallest_indent]
line_idexes_smalles_indents
的结果为[2, 7, 10]
。现在,我们需要根据这些索引对原始文本进行分区。
def partition(lines, indices):
return [''.join(lines[i:j]) for i, j in zip([0]+indices, indices+[None])]
partition(lines, line_idexes_smalles_indents)
结果:
['TextTextTextTextTextTextTextTextText1 TextTextTextTextTextTextTextTextText1',
' TextTextTextTextTextTextTextTextText2 TextTextTextTextTextTextTextTextText2 TextTextTextTextTextTextTextTextText2 TextTextTextTextTextTextTextTextText2 TextTextTextTextTextTextTextTextText2',
' TextTextTextTextTextTextTextTextText3 TextTextTextTextTextTextTextTextText3 TextTextTextTextTextTextTextTextText3',
' TextTextTextTextTextTextTextTextText4 TextTextTextTextTextTextTextTextText4 TextTextTextTextTextTextTextTextText4']