我想选择10个商家帐户,为每个商家帐户选择前15条交易记录,页面尺寸为10 * 50?
我有这个查询,该查询为我提供了最高记录,在这里我需要修正以选择“每个商人帐户ID的前15条记录”,而不仅仅是前150条记录。
欢迎任何指针,建议,代码修复!
SELECT * FROM (
SELECT account_id,transaction_id,ROWNUM RNUM
FROM transactions
WHERE status='P' AND ROWNUM < ( (p_page_number * p_page_size) + 1)
GROUP BY account_id,transaction_id, ROWNUM
ORDER BY account_id
) a
WHERE rnum >= ( ( (p_page_number - 1) * p_page_size) + 1);
这将为您提供“每个商人帐户ID的前15条记录”:
SELECT *
FROM (
SELECT
account_id,
transaction_id,
ROW_NUMBER() OVER(
PARTITION BY account_id -- Break into groups of merchants
ORDER BY transaction_id -- Assign row number based on transaction, within merchants
) RowNum
FROM transactions
WHERE status='P'
) src
WHERE src.RowNum <= 15
ORDER BY account_id, transaction_id
我不确定您的p_page_number, p_page_size, and ROWNUM
参数如何发挥作用。
您可以使用DENSE_RANK()
窗口功能将行分配组号,并使用ROW_NUMBER()
在每个组中分配序列号。然后过滤很容易。例如:
select
from (
select
account_id,
transaction_id,
dense_rank() over(order by account_id) as g,
row_number() over(partition by account_id order by transaction_id) as rn
from transactions
) x
where g <= 10 -- the first 10 groups (accounts)
and rn <= 15 -- the first 15 transactions within each group