从vimeo网址获取Vimeo id的简便方法

Question

我试图从vimeo URL获取id。有比这更简单的方法吗？我看到的所有vimeo视频网址总是：

https://vimeo.com/29474908

https://vimeo.com/38648446

// VIMEO


$vimeo = $_POST['vimeo'];

function getVimeoInfo($vimeo)
{
    $url = parse_url($vimeo);
    if($url['host'] !== 'vimeo.com' &&
            $url['host'] !== 'www.vimeo.com')
        return false;
   if (preg_match('~^http://(?:www\.)?vimeo\.com/(?:clip:)?(\d+)~', $vimeo, $match)) 
   {
       $id = $match[1];
   }
   else
   {
       $id = substr($link,10,strlen($link));
   }

   if (!function_exists('curl_init')) die('CURL is not installed!');
   $ch = curl_init();
   curl_setopt($ch, CURLOPT_URL, "http://vimeo.com/api/v2/video/$id.php");
   curl_setopt($ch, CURLOPT_HEADER, 0);
   curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
   curl_setopt($ch, CURLOPT_TIMEOUT, 10);
   $output = unserialize(curl_exec($ch));
   $output = $output[0];
   curl_close($ch);
   return $output['id'];
}

$vimeo_id = getVimeoInfo($vimeo);

Answer 1

我认为使用parse_url()是最好的选择：

$vimeo = 'https://vimeo.com/29474908';

echo (int) substr(parse_url($vimeo, PHP_URL_PATH), 1);

Answer 2

有许多有效的vimeo URL。很少有例子

所有有效的网址：

http://vimeo.com/6701902
http://vimeo.com/670190233
http://player.vimeo.com/video/67019023
http://player.vimeo.com/video/6701902
http://player.vimeo.com/video/67019022?title=0&byline=0&portrait=0
http://player.vimeo.com/video/6719022?title=0&byline=0&portrait=0
http://vimeo.com/channels/vimeogirls/6701902
http://vimeo.com/channels/vimeogirls/67019023
http://vimeo.com/channels/staffpicks/67019026
http://vimeo.com/15414122
http://vimeo.com/channels/vimeogirls/66882931

所有无效网址：

http://vimeo.com/videoschool
http://vimeo.com/videoschool/archive/behind_the_scenes
http://vimeo.com/forums/screening_room
http://vimeo.com/forums/screening_room/topic:42708

我写了这个java正则表达式，它捕获了所有上述有效的URL并拒绝了无效的URL。我不确定他们是否有更多有效的URL。

(https?://)?(www.)?(player.)?vimeo.com/([a-z]*/)*([0-9]{6,11})[?]?.*

希望这可以帮助...

Answer 3

对于那些想要看到使用PHP完全实现的代码的人，我使用的是用户2200660提供的正则表达式，并由Morgan Delaney为PHP格式化，这里是：

$vimeo = 'http://player.vimeo.com/video/67019023';

if(preg_match("/(https?:\/\/)?(www\.)?(player\.)?vimeo\.com\/([a-z]*\/)*([0-9]{6,11})[?]?.*/", $vimeo, $output_array)) {
    echo "Vimeo ID: $output_array[5]";
}

//outputs: Vimeo ID: 67019023

Answer 4

[编辑]您现在可以通过API完成所有操作！

如果您通过“links”参数向搜索端点（https://developer.vimeo.com/api/endpoints/videos#GET/videos）提供逗号分隔的Vimeo网址列表，我们会将这些视频作为API响应返回。

EG

GET https://api.vimeo.com/videos?links=https://vimeo.com/74648232,https://vimeo.com/232323497

[原版的]

Vimeo提供了许多不同类型的视频网址，其中一些不包含id。为了确保所有Vimeo网址的支持，您应该直接向vimeo索取ID。

你可以通过oEmbed endpoint询问vimeo。

有很多选项，但最简单的选择是向url https://vimeo.com/api/oembed.json?url={vimeo_url}发出HTTP GET请求，用适当的url替换{vimeo_url}。

例如，要获取上面提供的URL（https://vimeo.com/29474908）的ID，请发出HTTP GET请求

https://vimeo.com/api/oembed.json?url=https://vimeo.com/29474908

解析JSON响应，并获取video_id参数。

Answer 5

这应该从各种vimeo网址中检索ID。

$url = 'https://vimeo.com/cool/29474908?title=0&byline=0&portrait=0';
$urlParts = explode("/", parse_url($url, PHP_URL_PATH));
$videoId = (int)$urlParts[count($urlParts)-1];

Answer 6

当前正在运行的正则表达式：

function getIdFromVimeoURL(url) {
  return /(vimeo(pro)?\.com)\/(?:[^\d]+)?(\d+)\??(.*)?$/.exec(url)[3];
}

console.log(getIdFromVimeoURL("https://vimeo.com/channels/staffpicks/272053388"))
console.log(getIdFromVimeoURL("https://vimeo.com/272053388"))
console.log(getIdFromVimeoURL("https://player.vimeo.com/video/272053388"))

// ...etc.

Answer 7

如果有人在基于@ user2200660的JavaScript中需要它，请回答：

function getVimeoVideoId(url){

    var regex = new RegExp(/(https?:\/\/)?(www.)?(player.)?vimeo.com\/([a-z]*\/)*([0-9]{6,11})[?]?.*/);

    if ( regex.test(url) ) {
        return regex.exec(url)[5];
    }
}

Answer 8

如果您只需要视频IF，则可以使用RegEx非捕获组：

(?:https?:\/\/)?(?:www\.)?vimeo\.com\/(?:(?:[a-z0-9]*\/)*\/?)?([0-9]+)