我在Java中相对较新,并尝试将用户输入转换为十六进制。目前我正在尝试将其首先转换为Bytes,但是我遇到了一行qazxsw poi的错误
整体代码如下所示,
Byte getByte = Byte.parseByte(getCharacter);
我见过import java.util.ArrayList;
import java.util.Scanner;
public class Main {
public static void main(String[] args) {
// write your code here
Scanner scanner = new Scanner(System.in);
String name = scanner.next();
String binary = "", hexidecimal = "";
ArrayList<Character> chars = new ArrayList<>();
for(char c : name.toCharArray()) chars.add(c);
for(char c : chars) {
try {
String getCharacter = Character.toString(c);
Byte getByte = Byte.parseByte(getCharacter);
String stringByte = Byte.toString(getByte);
binary.concat(stringByte);
} catch (NumberFormatException e) {
e.printStackTrace();
}
}
System.out.println(binary);
}
}
然而我不明白如何将answers这样的东西加入到我的程序中。
如果您尝试将整个String转换为十六进制,最简单的方法是:
char a = '\uffff'
如果您绝对需要接受char而不是String,我认为最简单的解决方案是只转换为String然后转换为字节数组:
public class stringToHex {
public static void main(String[] args) throws UnsupportedEncodingException { //exception is necessary to convert to a byte array
String test = "Hello World";
byte[] bytes = test.getBytes("UTF-8"); //make a byte array out of the string
System.out.println(DatatypeConverter.printHexBinary(bytes)); //use DatetypeConverter to convert binary to hex
}
}