批处理文件：函数，创建特定字符的字符串，x次]] << [

Question

请帮助我的脚本不起作用。

@echo off
echo Printing repeated character
call :printStrings retVal 3 #
echo Returned String: "%retVal%"
PAUSE
:printStrings
(   
    setlocal EnableDelayedExpansion
    set /a "Number=%~2"
    rem set /a "counter=60-!Number!"
    set "returnStr="
    set "repeatChar=%~3"
    rem echo Character to repeat: %repeatChar%
    FOR /L %%G IN (1,1,!Number!) DO (
        set "returnStr=%returnStr%%repeatChar%"             
        echo Adding character
    )   
)
( 
    endlocal    
    set "%~1=%returnStr%"
    rem set "%~1=%repeatChar%"
    exit /b
)

我需要通过调用该函数来打印x特定字符的次数，所以如果我这样做的话

call :printStrings retVal 3 #

预期的输出将是

返回的字符串：“ ###”

请帮助我的脚本不起作用。 @echo off echo打印重复的字符调用：printStrings retVal 3＃echo返回的字符串：“％retVal％” PAUSE：printStrings（setlocal ...

Answer 1

您使用DelayedExpansion，但不在重要行上。set "returnStr=%returnStr%%repeatChar%"将失败，因为％returnStr％和％repeatChar％的扩展已完成。

Answer 2

::为什么使这么简单的事情复杂化