将3个SELECT语句组合以输出1个表

Question

我有三个查询结果。

查询1：

SELECT DISTINCT employeeid, work.clientid, ROUND ((CAST (AVG(current_lawn_price) AS numeric) / CAST (AVG((((EXTRACT(HOUR FROM job_finish)*60) + EXTRACT(MIN FROM job_finish))) - ((EXTRACT(HOUR FROM job_start)*60) + EXTRACT(MIN FROM job_start))) AS numeric)) / 1, 2) AS under_over_1
FROM work
JOIN timesheet USING (date_linkid)
JOIN client USING (clientid)
WHERE employeeid = 1 AND workid < 557 AND workid > 188
GROUP BY employeeid, clientid ORDER BY clientid ASC;

employeeid | clientid | under_over_1
------------+----------+--------------
          1 |        3 |         0.54
          1 |        4 |         0.47
          1 |        6 |         0.45
          1 |        7 |         0.59
          . |        . |           .
          . |        . |           .

查询2：

SELECT DISTINCT employeeid, work.clientid, ROUND ((CAST (AVG(current_lawn_price) AS numeric) / CAST (AVG((((EXTRACT(HOUR FROM job_finish)*60) + EXTRACT(MIN FROM job_finish))) - ((EXTRACT(HOUR FROM job_start)*60) + EXTRACT(MIN FROM job_start))) AS numeric)) / 1.31666666666667, 2) AS under_over_1
FROM work
JOIN timesheet USING (date_linkid)
JOIN client USING (clientid)
WHERE employeeid = 2
GROUP BY employeeid, clientid ORDER BY clientid ASC;

 employeeid | clientid | under_over_1
------------+----------+--------------
          2 |        2 |         1.01
          2 |        3 |         0.21
          2 |        4 |         0.71
          2 |        6 |         0.68
          . |        . |           .
          . |        . |           .

查询：3

SELECT DISTINCT employeeid, work.clientid, ROUND ((CAST (AVG(current_lawn_price) AS numeric) / CAST (AVG((((EXTRACT(HOUR FROM job_finish)*60) + EXTRACT(MIN FROM job_finish))) - ((EXTRACT(HOUR FROM job_start)*60) + EXTRACT(MIN FROM job_start))) AS numeric)) / 1.31666666666667, 2) AS under_over_1
FROM work
JOIN timesheet USING (date_linkid)
JOIN client USING (clientid)
WHERE employeeid = 3
GROUP BY employeeid, clientid ORDER BY clientid ASC;

 employeeid | clientid | under_over_1
------------+----------+--------------
          3 |        4 |         0.70
          3 |        6 |         0.54
          3 |        7 |         1.03
          3 |       11 |         0.74
          . |        . |           .
          . |        . |           .

我想输出一个包含所有三个查询结果的表，（（很抱歉，但是我必须在这里写更多的东西，这样我才能提交这篇文章。我希望这足够了;-)）：]]

employeeid | clientid | under_over_1
------------+----------+--------------
          1 |        3 |         0.54
          1 |        4 |         0.47
          1 |        6 |         0.45
          1 |        7 |         0.59
          . |        . |           .
          . |        . |           .
          2 |        2 |         1.01
          2 |        3 |         0.21
          2 |        4 |         0.71
          2 |        6 |         0.68
          . |        . |           .
          . |        . |           .
          3 |        4 |         0.70
          3 |        6 |         0.54
          3 |        7 |         1.03
          3 |       11 |         0.74
          . |        . |           .
          . |        . |           .
我尝试过UNION ALL，例如

SELECT DISTINCT employeeid, work.clientid, ROUND ((CAST (AVG(current_lawn_price) AS numeric) / CAST (AVG((((EXTRACT(HOUR FROM job_finish)*60) + EXTRACT(MIN FROM job_finish))) - ((EXTRACT(HOUR FROM job_start)*60) + EXTRACT(MIN FROM job_start))) AS numeric)) / 1, 2) AS under_over_1
FROM work
JOIN timesheet USING (date_linkid)
JOIN client USING (clientid)
WHERE employeeid = 1 AND workid < 557 AND workid > 188
GROUP BY employeeid, clientid ORDER BY clientid ASC

UNION ALL

SELECT DISTINCT employeeid, work.clientid, ROUND ((CAST (AVG(current_lawn_price) AS numeric) / CAST (AVG((((EXTRACT(HOUR FROM job_finish)*60) + EXTRACT(MIN FROM job_finish))) - ((EXTRACT(HOUR FROM job_start)*60) + EXTRACT(MIN FROM job_start))) AS numeric)) / 1.31666666666667, 2) AS under_over_1
FROM work
JOIN timesheet USING (date_linkid)
JOIN client USING (clientid)
WHERE employeeid = 3
GROUP BY employeeid, clientid ORDER BY clientid ASC

UNION ALL

SELECT DISTINCT employeeid, work.clientid, ROUND ((CAST (AVG(current_lawn_price) AS numeric) / CAST (AVG((((EXTRACT(HOUR FROM job_finish)*60) + EXTRACT(MIN FROM job_finish))) - ((EXTRACT(HOUR FROM job_start)*60) + EXTRACT(MIN FROM job_start))) AS numeric)) / 1.31666666666667, 2) AS under_over_1
FROM work
JOIN timesheet USING (date_linkid)
JOIN client USING (clientid)
WHERE employeeid = 2
GROUP BY employeeid, clientid ORDER BY clientid ASC;
但是，出现以下错误：

ERROR:  syntax error at or near "UNION"
LINE 7: UNION ALL

我不确定为什么这是错误的，或者UNION ALL在这里是否正确。有人知道吗？

我有三个查询结果。查询1：SELECT DISTINCT employeeid，work.clientid，ROUND（（CAST（AVG（current_lawn_price）AS数值）/ CAST（AVG（（（（（（EXTRACT（HOUR FROM job_finish）* 60）+ EXTRACT（...

Answer 1

导致错误的直接原因是引用the manual：

Answer 2

删除所有ORDER BY。然后将结果查询用作派生表。要保留您想要的顺序，可以使用CASE表达式将employeeid映射到整数并确定顺序：