如何使用Java中的基于构造函数的初始化来初始化WebClient?

问题描述 投票:3回答:2

我试图从WebClient替换RestTemplate,因为根据Java Doc,将不建议使用RestTemplate。 Spring团队建议尽可能使用WebClient。

RestTempalte的先前代码如下

public Map<String,String> getInfo()
    {
        HttpHeaders headers = new HttpHeaders();
        headers.set( ACCEPT, MediaType.APPLICATION_JSON_VALUE );
        HttpEntity<?> entity = new HttpEntity<>( headers );
        UriComponentsBuilder builder = UriComponentsBuilder.fromHttpUrl( this.endpoint + VERSION_INFO_PATH );

        RestTemplate restTemplate = new RestTemplate();
        ResponseEntity<CPResponse> response = restTemplate.exchange(
                builder.toUriString(),
                HttpMethod.GET,
                entity,
                CPResponse.class );


        List<Object> resultList = response.getBody().getResults();

        if( response.getBody().getResults() != null && !( resultList )
                                                                .isEmpty() )
        {

            return ( ( LinkedHashMap ) resultList.get( 0 ) );
        }
        else
        {
            throw new CrawlerRuntimeExceptions( "Invalid response from API" );
        }

    }

我想从WebClient替换RestTemplate。因此,我实现了WebClientConnection类,如下所示

public class WebClientConnection
{
   private WebClient webClient;


    public WebClientConnection( String baseUrl )
    {
        this.webClient = WebClient.create( baseUrl );

    }

    public  Mono<CPResponse> get( String url )
    {
        return webClient.get().uri( "/{url}",url ).retrieve().bodyToMono( CPResponse.class );
    }

    public  Flux<CPResponse> getAll( String url )
    {
        return webClient.get().uri( "/{url}",url ).retrieve().bodyToFlux( CPResponse.class );
    }

    public  Mono<CPResponse> post( String url, HttpEntity entity )
    {
        return webClient.post().uri( "/{url}",url ).retrieve().bodyToMono( CPResponse.class );
    }
}

我使用此依赖项

<dependency>
   <groupId>org.springframework.boot</groupId>
   <artifactId>spring-boot-starter-webflux</artifactId>
   <version>>2.1.3.RELEASE</version>
</dependency>
public void getInfo()
    {
        WebClientConnection webClientConnection = new WebClientConnection( endpoint );
        Mono<CPResponse> response = webClientConnection.get( VERSION_INFO_PATH );
    }

在webclient创建上有stackOverflow错误

public WebClientConnection( String baseUrl )
    {
        this.webClient = WebClient.create( baseUrl );

    }

如何正确完成从RestTemplate到WebClient的迁移?

java spring-mvc reactive-programming spring-webflux spring-webclient
2个回答
1
投票

实际上是StackOverflow异常javadoc

由于应用程序递归而在发生堆栈溢出时抛出太深了。

(很好的解释here

本身,创建WebClient并不包含此类递归。也许您在某处使用(隐式)递归?

堆栈跟踪可以帮助找出问题所在。


0
投票

我找出了问题。它与代码问题有关。添加后>

   <parent>
        <groupId>org.springframework.boot</groupId>
        <artifactId>spring-boot-starter-parent</artifactId>
        <version>2.0.2.RELEASE</version>
        <relativePath/> <!-- lookup parent from repository -->
    </parent>

到pom并按如下所示修改WebClientConnection类。

public class WebClientConnection
{
    private final WebClient webClient;
    private static final String API_MIME_TYPE = "application/json";
    private static final String API_BASE_URL = "http://localhost:8080";
    private static final String USER_AGENT = "Spring 5 WebClient";

    public WebClientConnection( )
    {
        this.webClient = WebClient.builder()
                                  .baseUrl(API_BASE_URL)
                                  .defaultHeader(HttpHeaders.CONTENT_TYPE, API_MIME_TYPE)
                                  .defaultHeader(HttpHeaders.USER_AGENT, USER_AGENT)
                                  .build();
    }

    public  Mono<CPResponse> get( String url )
    {
        return webClient.get().uri( "/{url}",url ).retrieve().bodyToMono( CPResponse.class );
    }

    public  Flux<CPResponse> getAll( String url )
    {
        return webClient.get().uri( "/{url}",url ).retrieve().bodyToFlux( CPResponse.class );
    }

    public  Mono<CPResponse> post( String url, HttpEntity entity )
    {
        return webClient.post().uri( "/{url}",url ).retrieve().bodyToMono( CPResponse.class );
    }
}

然后问题已解决。

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