我需要帮助来确定GraphQL标签以用于Apollo Client。文档并没有超出最基本的突变用例。
我的目标是使唯一需要的输入是电子邮件。如果存在其他变量,我希望这些变量可以被接受并创建包含所有这些信息的提案。
我有一个变异(仅在电子邮件和完整变量情况下)在GraphQl Playground上成功运行(如果有帮助,您可以在这里找到它并进行测试,查看模式等):https://prisma2-graphql-yoga-shield.now.sh/playground )
mutation {
createOneProposal(
data: {
email: "[email protected]"
name: "Sean"
types: {
create: {
model: PURCHASE
name: "e-commerce"
cost: 600
services: {
create: [
{ service: "Responsive web design" }
{ service: "Another service!" }
{ service: "And yet another service!" }
]
}
}
}
}
) {
created_at
proposal_id
types {
cost
model
name
type_id
services {
service
service_id
}
}
}
}
结果生产:
{
"data": {
"createOneProposal": {
"created_at": "2020-02-27T21:28:53.256Z",
"proposal_id": 35,
"types": [
{
"cost": 600,
"model": "PURCHASE",
"name": "e-commerce",
"type_id": 6,
"services": [
{
"service": "Responsive web design",
"service_id": 10
},
{
"service": "Another service!",
"service_id": 11
},
{
"service": "And yet another service!",
"service_id": 12
}
]
}
]
}
}
}
我对gql标签的初始设计:
export const NEW_PROPOSAL = gql`
mutation createOneProposal(
$email: String!
$name: String
$cost: Int
$model: Model
$service: Service
) {
createOneProposal(
email: $email
name: $name
cost: $cost
model: $model
service: $service
) {
created_at
proposal_id
types {
services {
service_id
}
}
}
}
`;
但是,与此有关的很多错误。
{"errors":[
{"Variable "$service" cannot be non-input type `"Service`".","locations":[{"line":1,"column":97}]},
{"Unknown argument "email" on field "createOneProposal`" of type "Mutation`".","locations":[{"line":2,"column":21}]},
{"Unknown argument "name" on field "createOneProposal`" of type "Mutation`".","locations":[{"line":2,"column":36}]},
{"Unknown argument"cost" on field "createOneProposal\" of type "Mutation`".","locations":[{"line":2,"column":49}]},
{"Unknown argument "model" on field "createOneProposal`" of type "Mutation`".","locations":[{"line":2,"column":62}]},
{"Unknown argument "service" on field "createOneProposal`" of type "Mutation`".","locations":[{"line":2,"column":77}]},
{"Field "createOneProposal" argument "data" of type "ProposalCreateInput!`" is required, but it was not provided.","locations":[{"line":2,"column":3}]}]}
所以,我该怎么做...我想出了查询版本(要容易得多...),但是我却无法弄清楚!
我的模式,如果有帮助:
generator client {
provider = "prisma-client-js"
}
datasource db {
provider = "mysql"
url = env("MYSQL_URL_PRISMA2")
}
model Post {
content String @default("")
created_at DateTime @default(now())
post_id Int @default(autoincrement()) @id
published Boolean @default(false)
published_at DateTime?
title String @default("")
author User
}
model Profile {
bio String?
profile_id Int @default(autoincrement()) @id
user_id User
}
model Proposal {
email String @unique
name String?
proposal_id Int @default(autoincrement()) @id
created_at DateTime @default(now())
types Type[]
}
model Type {
cost Int?
name String?
model Model? @default(SUBSCRIPTION)
services Service[]
type_id Int @default(autoincrement()) @id
proposal_id Proposal
}
model Service {
service_id Int @default(autoincrement()) @id
service String?
type_id Type
}
model User {
email String @default("") @unique
name String @default("")
password String @default("")
role Role @default(USER)
user_id Int @default(autoincrement()) @id
posts Post[]
profiles Profile[]
}
enum Role {
USER ADMIN
}
enum Model {
SUBSCRIPTION PURCHASE CUSTOM
}
输出类型。输入类型用于诸如变量定义或参数定义之类的输入。输出类型用于键入字段,这些字段构成实际的响应。标量和枚举之类的某些类型可以用作输入或输出。但是,对于对象,存在输出对象类型(有时仅称为对象类型或对象)和输入对象类型。
Service
是输出类型,因此不能在需要输入类型的情况下使用(在这种情况下为变量定义)。检查Prisma生成的架构,以确定要使用的适当类型。mutation createOneProposal($input: ProposalCreateInput!){
createOneProposal(data:$input){
created_at
name
email
proposal_id
type{
cost
description
model
name
type_id
services{
service
cost
service_id
}
}
}
}