SQL JOIN：如何回显与表B列同名的表A列的值？

Question

我有两个MySQL表，名称为accounts

id username role
1  pete101  2
2  JohnnyA  1
3  Anno65   1
4  tom      1
5  koala3   2

并且名称为事件

id date     accountID
1  02-04-20 3
2  10-04-20 5
3  07-04-20 4
4  10-04-20 2
5  10-04-20 1

现在，我要在HTML表格中显示角色为'2'的帐户中所有日期为'10 -04-20'的事件。我为此使用此查询："SELECT * FROM events JOIN accounts ON events.accountID = accounts.id WHERE events.date = '10-04-20' AND accounts.role = '2'"

while($row = mysqli_fetch_array($result)){   
    echo "<tr><td>" . $row['id'] . "</td><td>" . $row['date'] . "</td><td>" . $row['username'] . "</td><td>" . $row['accountID'] . "</td><br>"; 
}

此查询（和PHP）的结果是下一个：

id  date     username accountID
5  10-04-20  koala3   5
1  10-04-20  pete101  1

它显示accounts表的ID的两倍，但我想要下一个回显：

id  date     username accountID
2  10-04-20  koala3   5
5  10-04-20  pete101  1

所以第一列是events表的ID，最后一列（accountID）是accounts表的ID

我该怎么做才能解决此问题？

非常感谢！

Answer 1

尝试

CREATE TABLE accounts
    (`id` int, `username` varchar(7), `role` int)
;

INSERT INTO accounts
    (`id`, `username`, `role`)
VALUES
    (1, 'pete101', 2),
    (2, 'JohnnyA', 1),
    (3, 'Anno65', 1),
    (4, 'tom', 1),
    (5, 'koala3', 2)
;

✓✓

CREATE TABLE events
    (`id` int,  `date` date, `accountID` varchar(10))
;

INSERT INTO events
    (`id`, `date`, `accountID`)
VALUES
    (1, '02-04-20', 3),
    (2, '10-04-20', 5),
    (3, '07-04-20', 4),
    (4, '10-04-20', 2),
    (5, '10-04-20', 1)
;

✓✓

SELECT 
e.id,a.username,e.`date`, e.accountID
FROM events e JOIN accounts a ON e.accountID = a.id 
 WHERE e.date = '10-04-20' AND a.role = '2'
Order BY e.id

id |用户名|日期|帐户ID-：| ：------- | ：--------- | ：--------2 | koala3 | 2010-04-20 | 55 | pete101 | 2010-04-20 | 1个

db <>小提琴here

Answer 2

由于它有助于评论，也可以作为答案。将其从$row['colname'];更改为其在$row]中的实际位置

更改原始查询：

while($row = mysqli_fetch_array($result)){   
    echo "<tr><td>" . $row['id'] . "</td><td>" . $row['date'] . "</td><td>" . $row['username'] . "</td><td>" . $row['accountID'] . "</td><br>"; 
}
为此：

while($row = mysqli_fetch_array($result)){   
    echo "<tr><td>" . $row[0] . "</td><td>" . $row[1] . "</td><td>" . $row[2] . "</td><td>" . $row[3] . "</td><br>"; 
}