添加static_pointer_cast 到std :: list >导致称为错误的纯虚方法

问题描述 投票:0回答:1

我有这个基类

class Base {

    std::string nome;

public:
    std::string getName() const;
    virtual int mType() const = 0;
    virtual void ls(int indent=0) const = 0;
};

我从中派生了这个Directory类

class Directory : public Base {

private:
    static std::shared_ptr<Directory> root;
    std::list<std::shared_ptr<Base>> childs;
    std::weak_ptr<Directory> parent;
    std::weak_ptr<Directory> thisDirectory;
    std::string nome;

protected:
    Directory(const std::string n);

public:
    static std::shared_ptr<Directory> getRoot();
    std::shared_ptr<Directory> addDirectory(std::string nome);
    std::shared_ptr<File> addFile(std::string nome, uintmax_t size);
    std::shared_ptr<Base> get(std::string name);
    std::shared_ptr<Directory> getDir(std::string name);
    std::shared_ptr<File> getFile(std::string name);
    void remove(std::string nome);

    int mType() const override;
    void ls(int indent=0) const override;
};

方法addDirectory

std::shared_ptr<Directory> Directory::addDirectory(std::string nome) {
    auto it = std::find_if(childs.begin(), childs.end(), [nome](std::shared_ptr<Base> p){return (p->getName()==nome);});
    if(it == childs.end()){
        std::cout<<"creating "<<nome<<" directory"<<std::endl;
        std::shared_ptr<Directory> p = std::shared_ptr<Directory>(new Directory(nome));
        childs.push_back(std::static_pointer_cast<Base>(p));
        p->parent = std::shared_ptr<Directory>(this);
        std::cout<<nome<<" created"<<std::endl;
        return p;
    }
    else {
        // todo gestione eccezione
        std::cout<<nome<<" already exists"<<std::endl;
        throw std::exception();
    }
}

将打印此输出

pure virtual method called
creating root...
terminate called recursively
root created
creating alfa directory
alfa created

pure virtual method called是由childs.push_back(std::static_pointer_cast<Base>(p));引起的,而terminate called recursively是由p->parent = std::shared_ptr<Directory>(this);引起的。使用childs.push_back(p)工作正常,为什么?它是否尝试创建Base对象的实例?我可以通过对Base类使用shared_ptr来管理派生类对象的列表吗?

c++ casting virtual shared-ptr
1个回答
0
投票

你必须使用enable_shared_from_this才能从shared_ptr创建一个this

将您的班级声明更改为......

class Directory : public Base, public std::enable_shared_from_this<Directory>

并用std::shared_ptr<Directory>(this)取代shared_from_this()。还要确保使用共享指针构造所有目录(包括根目录)。

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