我有一个表'temp',它的ID和它的直接父ID为列。下表如下:
1
/ \
2 3
/|\ \
4 5 6 7
/
8
节点的层次结构可以用上面的树结构表示。
现在,我要使用具有级别(如Level1,Level2等)作为属性的recursive cte列出透视表中所有级别上存在的每个节点的所有祖先节点或父节点。为了获得此输出,我计算了非数据透视表中的所有父节点,每个节点相对于其父节点的级别。如下的sql查询:
WITH ctetable as
(
SELECT S.id, S.parent, 1 as level
FROM temp as S where S.parent is not null
UNION ALL
SELECT S2.id, p.parent, p.level + 1
FROM ctetable AS p JOIN temp as S2 on S2.parent = p.id
)
SELECT * FROM ctetable ORDER BY id;
以上查询的输出如下所示:
但是,我想透视包含特定节点每个级别下的父ID的递归cte。说,对于id = 4,它应该分别在Level3,Level2和Level1下显示父ID 4、2和1。为此,我编写了以下查询:
WITH ctetable as
(
SELECT S.id, S.parent, 1 as level
FROM temp as S where S.parent is not null
UNION ALL
SELECT S2.id, p.parent, p.level + 1
FROM ctetable AS p JOIN temp as S2 on S2.parent = p.id
)
SELECT
myid,
[pn].[1] AS [Level1],
[pn].[2] AS [Level2],
[pn].[3] AS [Level3]
FROM
(
SELECT [a].id,
[a].id as myid,
[a].level
FROM ctetable AS [a]
) AS [hn] PIVOT(max([hn].id) FOR [hn].level IN([1],[2],[3])) AS [pn]
但是,输出表不是所需的表,因为它包含与特定节点的每个级别下的父代ID重复的相同ID,相反,它应该包含该节点在各个级别下的所有父代。我执行上述查询后得到的输出如下所示:
有人可以帮我这个忙吗?...
如果您的水平已知或最大,并且假设我没有扭转您想要的结果。
也最好以文本形式而不是以图像形式发布样本数据和所需结果
示例
Declare @YourTable Table ([id] int,[parent] int)
Insert Into @YourTable Values
(1,null)
,(2,1)
,(3,1)
,(7,3)
,(4,2)
,(5,2)
,(6,2)
,(8,4)
;with cteP as (
Select id
,Parent
,PathID = cast(id as varchar(500))
From @YourTable
Where Parent is Null
Union All
Select id = r.id
,Parent = r.Parent
,PathID = cast(concat(p.PathID,',',r.id) as varchar(500)) -- Perhaps I reversed the desired sequence
From @YourTable r
Join cteP p on r.Parent = p.id)
Select ID
,B.*
From cteP A
Cross Apply (
Select Level1 = xDim.value('/x[1]','int')
,Level2 = xDim.value('/x[2]','int')
,Level3 = xDim.value('/x[3]','int')
,Level4 = xDim.value('/x[4]','int')
,Level5 = xDim.value('/x[5]','int')
From (Select Cast('<x>' + replace(PathID,',','</x><x>')+'</x>' as xml) as xDim) as X
) B
Order By PathID
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