我正在制作井字游戏，在这个玩家类中我有玩家 X 和 O。我希望能够添加另一个玩家

Question

添加另一个玩家时，如果有 3 个玩家，则角色应该是 X O P；如果有 4 个玩家，那么它应该是 X O P Q。我正在考虑使用带有 NumbOfPlayers 和 PlayerName 的 if 循环，但我迷路了。代码是Java

public class Player {
    private Controller controller;
    private char PlayerName=88;
    
    private int NumbOfPlay=3;
    

    public Player(Controller _controller, char PlayerName) {
        this.controller = _controller;
        
    }

    public char getName() {
        return PlayerName;
    }

    public char getSymbol() {
        return PlayerName;
    }
    //goes to the next player
    public void NP() {
        
          if (PlayerName == 88) {
                PlayerName = 79;
            } else {
                PlayerName = 88;
            }
    }
}

Answer 1

利用 Deque 类和 static 上下文。

class Player {
    String s;
    char c;
    static Deque<Character> deque = new ArrayDeque<>(List.of('X', 'O', 'P', 'Q'));

    Player(char c) {
        this.c = c;
    }

    static Player get() {
        if (deque.isEmpty()) return null;
        return new Player(deque.pop());
    }
}

Player x = Player.get();
Player o = Player.get();
Player p = Player.get();
Player q = Player.get();