如何通过使用if / else语句将重复的数字与未重复的数字分为两个列表？

Question

我能够找到一种方法来比较三个列表中的所有数字。如果所有三个列表中都存在一个数字，则必须将其添加到matching_numbers列表中。如果一个数字与其他任何数字都不匹配，那么我将不得不将其添加到unique_numbers列表中。在三个列表中的两个列表中找到的重复项被视为唯一编号，因此应将其放入unique_numbers列表中。

list_1 = []

list_2 = []

list_3 = []

matching_numbers = []

unique_numbers = []

countone = 0

counttwo = 0

countthree = 0

exit = 0

import random

name = input("Hello USER. What will your name be?")

print("Hello " + name + ". Welcome to the NUMBERS program.")

amountone = int(input("How many numbers do you wish to have for your first list? Please choose from between 1 and 15."))

while countone != amountone:
  x = random.randint(1, 30)
  list_1 += [x,]
  print(list_1)
  countone += 1

amounttwo = int(input("For your second list, how many numbers do you wish to have? Please choose from between 1 and 15."))

while counttwo != amounttwo:
  x = random.randint(1, 30)
  list_2 += [x,]
  print(list_2)
  counttwo += 1

amountthree = int(input("For your third list, how many numbers do you wish to have? Please choose from between 1 and 15."))

while countthree != amountthree:
  x = random.randint(1, 30)
  list_3 += [x,]
  print(list_3)
  countthree += 1

for a in list_1:
  for b in list_2:
    for c in list_3:
      if a == b and b == c:
        matching_numbers = list(set(list_1) & set(list_2) & set(list_3))
      else:
        unique_numbers = 

Answer 1

仅使用列表方法，（您也可以使用集合或collections.Counter），您可以执行以下操作：

def separate(*lists):
    unique_values = []
    duplicate_values = []
    for list_ in lists:
        for value in list_:
            if all(value in l for l in lists):
                if value not in duplicate_values:
                    duplicate_values.append(value)
            else:
                if value not in unique_values:
                    unique_values.append(value)
     return unique_values, duplicate_values

我鼓励您尝试使用集合重写此代码，以了解它们如何使此代码更快，更简单。

Answer 2

尝试使用集：

import random

list_1 = [random.randint(0, 30) for _ in range(30)]
list_2 = [random.randint(0, 30) for _ in range(30)]
list_3 = [random.randint(0, 30) for _ in range(30)]

matched_numbers =set.union(set(list_1).intersection(set(list_2)), set(list_1).intersection(set(list_3)), set(list_2).intersection(set(list_3)))
unique_numbers = set.difference(set.union(set(list_1), set(list_2), set(list_3)), matched)