Rust：由于道具转义函数体而无法调用回调

Question

#[derive(PartialEq, Properties)]
pub struct ItemProps {
    cost: i128,
    purchaseCallback: Callback<i32>,
    name: String,
    imgUrl: String,
    cookiesPerSecond: i128,
    itemIndex: i32,
}

#[function_component]
pub fn Item(props: &ItemProps) -> Html {
    let ItemProps {cost, purchaseCallback, name, imgUrl, cookiesPerSecond, itemIndex} = props;
    let onclick: Callback<MouseEvent> = Callback::from(move |_| {
        purchaseCallback.emit(*itemIndex);
    });

    html! {
        <div class="item">
            <img src={imgUrl.as_str()} />
            <span class="item-name">{name.as_str()}</span>
            <span class="item-cost">{cost}</span>
            <button {onclick}></button>
        </div>
    }
}

错误信息：

  --> src/main.rs:20:41
   |
18 |   pub fn Item(props: &ItemProps) -> Html {
   |               -----  - let's call the lifetime of this reference `'1`
   |               |
   |               `props` is a reference that is only valid in the function body
19 |       let ItemProps {cost, purchaseCallback, name, imgUrl, cookiesPerSecond, itemIndex} = props;
20 |       let onclick: Callback<MouseEvent> = Callback::from(move |_| {
   |  _________________________________________^
21 | |         purchaseCallback.emit(*itemIndex);
22 | |     });
   | |      ^
   | |      |
   | |______`props` escapes the function body here
   |        argument requires that `'1` must outlive `'static`

我正在使用紫杉网络组装框架在 Rust 中构建一个组件。我遇到了一个错误，当我尝试调用回调函数时它给了我一个错误，因为 props 变量转义了函数体。