---property---
id | ozellik
1 | "random"
2 | "fast"
3 | "red"
-----------
----property_cafe--------
id | cafe_id | property_id
1 | 1 | 1
2 | 1 | 2
3 | 1 | 3
-----------------------
---cafe---
id | name
1 | lorem
-----------------
property.id = property_cafe.property_id
cafe.id = property_cafe.cafe_id
复选框选择1,2,3。我希望看到具有1,2,3 id特征的咖啡馆的功能。
我可以创建一个单独的查询,但我有无限的功能表接近100,我找不到解决方案。
使用WHERE property.id IN (?, ?, ?, ...)
创建查询,您可以根据复选框值数组的大小动态构建问号列表。
$where_count = count($_POST['property']);
$questions = '?' . str_repeat(', ?', $where_count-1);
$sql = "SELECT c.name, GROUP_CONCAT(p.ozellik) AS ozellik
FROM cafe AS c
JOIN property_cafe AS pc ON pc.cafe_id = c.id
JOIN property AS p ON pc.property_id = p.id
WHERE p.id IN ($questions)
GROUP BY c.id
HAVING COUNT(*) = ?";
$stmt = $pdo->prepare($sql);
$params = $_POST['property'];
$params[] = $where_count;
$stmt->execute($params);
将数组传递给$stmt->execute()
使用元素填充SQL中的?
占位符。
有关编写查询以查找具有所有属性的所有咖啡馆的各种方法,请参阅How to return rows that have the same column values in MySql。这是制作此动态SQL的最简单方法。
假设您的复选框写成:
<input type="checkbox" name="property[]" value="1"> Random
<input type="checkbox" name="property[]" value="2"> Fast
<input type="checkbox" name="property[]" value="3"> Red