我想添加一个参数,但是我也有一个主体,我想形成这种格式:
HttpPost
http://localhost:8080/master/public/api/v1/invoice/send?token=123456
目前我有:
HttpPost
http://localhost:8080/master/public/api/v1/invoice/send
private readonly string UrlBase = "http://localhost:8080";
private readonly string ServicePrefix = "master/public/api";
public async Task<DocumentResponse> SendInvoice<T>(Invoice body)
{
string controller = "/v1/invoice/send";
try
{
var request = JsonConvert.SerializeObject(body);
var content = new StringContent(
request, Encoding.UTF8,
"application/json");
var client = new HttpClient();
client.BaseAddress = new Uri(UrlBase);
var url = string.Format("{0}{1}", ServicePrefix, controller);
var response = await client.PostAsync(url, content);
Debug.WriteLine(response);
var result = await response.Content.ReadAsStringAsync();
if (!response.IsSuccessStatusCode)
{
return new DocumentResponse
{
};
}
var list = JsonConvert.DeserializeObject<DocumentResponse>(result);
return list;
}
catch (Exception ex)
{
Debug.WriteLine(ex.ToString());
return new DocumentResponse
{
};
}
}
当我直接将其添加到url时,请求失败。
高级
当我直接将其添加到url时,请求失败。在查询HttpClient时,我发现了这一点,但是如何添加它的正文?
var parameters = new Dictionary<string, string> { { "token", "123456" } };
var encodedContent = new FormUrlEncodedContent (parameters);
参考:C#: HttpClient with POST parameters
谢谢
[格式化网址时,您需要像这样添加参数:
var url = string.Format("{0}{1}", ServicePrefix, controller);
url = string.Format("{0}?token=123456", url);
请注意URL和查询参数之间的?
。
您没有指定如何将token
的值添加到方法中,但是,如果它是类似于readonly
的ServicePrefix
值,则可以将其作为参数传递给string.Format:
var url = string.Format("{0}{1}", ServicePrefix, controller);
url = string.Format("{0}?token={1}", url, Token);
您总是可以将其放在一行上,但为了方便阅读,我将其拆分了:-)