Java代码不会改变人类岁月的年龄

Question

我正在尝试做一个程序，将输入的狗的年龄转换成人类的岁月，但这是行不通的。以下是我将狗年转换为人年的说明：一种方法[[inHumanYears，该方法将返回宠物狗的年龄（以人为单位）。这是计算方法：

15人年等于中型犬生命的第一年。
• [狗的第二年相当于一个人的九年。
• 此后，每条狗的人年寿命约为5年。

这里有几个例子：

[4个月大的狗= 0.25（一年的1/4）* 15 = 3.75人年]

5岁= 15 + 9 +（5-2）* 5 = 39人年

有人可以帮我吗？这是我到目前为止得到的代码：

java.util.Scanner;
public class MyPet_1_lab7 {
    // Implement the class MyPet_1 so that it contains 3 instance variables
        private String breed;
        private String name;
        private int age;
        private double inHumanYears;
    // Default constructor
        public MyPet_1_lab7()
        {
            this.breed = null;
            this.name = null;
            this.age = 0;
        }
    // Constructor with 3 parameters
        public MyPet_1_lab7(String a_breed, String a_name, int an_age){
            this.breed = a_breed;
            this.name = a_name;
            this.age = an_age;
        }
    // Accessor methods for each instance variable
        public String getBreed(){
            return this.breed;
        }
        public String getName(){
            return this.name;
        }
        public int getAge(){
            return this.age;
        }
    //Mutator methods for each instance variable
        public void setBreed(String a_breed){
            this.breed = a_breed;
        }
        public void setName(String a_name){
            this.name = a_name;
        }
        public void setAge(int an_age){
            this.age = an_age;
        }
    // toString method that will return the data in an object formated as per the output
        public String toString(){
            return (this.breed + " whose name is " + this.name + " and " + this.age + " dog years (" + inHumanYears + " human years old)");
        }
        public boolean equals(MyPet_1_lab7 a){
            if ((this.breed == a.getBreed()) && (this.age == a.getAge())){
                return true;
            }
            else
                return false;
        }
        public double inHumanYears(){
            if (age >= 2 ){
                inHumanYears = (15 + 9 + (age - 2))*5;
                return (inHumanYears);
                }
            else {
                inHumanYears = (age/12)*15;
                return (inHumanYears);
            }
        }
    public static void main(String[] args) {
        Scanner keyboard = new Scanner (System.in);
        System.out.print("What type of dog do you have? ");
        String breed = keyboard.nextLine();

        System.out.print("What is its name? ");
        String name = keyboard.nextLine();

        System.out.print("How old? ");
        int age = keyboard.nextInt();
        MyPet_1_lab7 dog= new MyPet_1_lab7();
        System.out.println(dog);
        MyPet_1_lab7 dog1 = new MyPet_1_lab7(breed,name,age);
        System.out.println(dog1);



    }

}
'''

Answer 1

问题是您的toString()方法使用尚未调用的方法访问您的

set字段。这个

public String toString(){
    return (this.breed + " whose name is " + this.name + " and " 
            + this.age + " dog years (" + inHumanYears + " human years old)");
}

应更改为调用inHumanYears()。喜欢，
public String toString(){
    return (this.breed + " whose name is " + this.name + " and " 
            + this.age + " dog years (" + inHumanYears() + " human years old)");
}