makefile-如何读取三个元素列表？

Question

下面是捕获标记参数的代码：

.PHONY: tag

tag:
    ${INFO} "Tag image with tags $(LIST_ARGS)..."
    # use a, b, c

ifeq (tag, $(firstword $(MAKECMDGOALS)))
    LIST_ARGS := $(wordlist 2,$(words $(MAKECMDGOALS)), $(MAKECMDGOALS))
    ifeq ($(LIST_ARGS),)
        $(error You must specify a tag)
    endif
    $(eval $(LIST_ARGS):;@:)  # # Do not interpret "tag" arguments as make target files
    # Copy three element list to variables a, b & c 
endif

---

正在运行make tag 1.1 44 ds23，

[LIST_ARGS存储值1.1 44 ds23

[a应存储1.1

[b应存储44

[c应存储ds23

---

如何从此$(LIST_ARGS)中读取每个值并分别存储在单独的变量a，b和c中？在任务tag中]

下面是捕获标记参数的代码：.PHONY：标记标记：$ {INFO}“带有标记$（LIST_ARGS）...的标记图像...”＃使用a，b，c ifeq（标记，$（firstword $ （MAKECMDGOALS）））LIST_ARGS：= $（...

Answer 1

a = $(word 1,$(LIST_ARGS))
b = $(word 2,$(LIST_ARGS))
c = $(word 3,$(LIST_ARGS))

Answer 2

没问题：