将行移置为列

问题描述 投票:0回答:1

需要将列转置为行。

Input Data

i具有预定义的列。如果存在该记录,则在相应列中将列值填充为“是”,否则默认为“否”。

预期的列集如下:Col_A,Col_D,Col_X,Col_T,Col_M,Col_E

Output Data

让我知道任何问题

hive hiveql
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投票

表转置(输入数据)

+--------+---------+
| col_id | col_val |
+--------+---------+
| axc    | col_x   |
| bdf    | col_f   |
| cde    | col_x   |
| yhc    | col_b   |
| idx    | col_a   |
| dft    | col_y   |
+--------+---------+

配置单元查询以转置col_val:

 SELECT a.col_id,IF(array_contains(collect_list(a.map_values['col_x']),'1'),'Y','N') AS col_x,
IF(array_contains(collect_list(a.map_values['col_y']),'1'),'Y','N') AS col_y,
IF(array_contains(collect_list(a.map_values['col_a']),'1'),'Y','N') AS col_a,
IF(array_contains(collect_list(a.map_values['col_b']),'1'),'Y','N') AS col_b,
IF(array_contains(collect_list(a.map_values['col_f']),'1'),'Y','N') AS col_f FROM (
       SELECT col_id,
              col_val,
              map(col_val, '1') map_values
       FROM   transpose) a GROUP BY a.col_id; 

结果

+--------+-------+-------+-------+-------+-------+
| col_id | col_x | col_y | col_a | col_b | col_f |
+--------+-------+-------+-------+-------+-------+
| axc    | Y     | N     | N     | N     | N     |
| bdf    | N     | N     | N     | N     | Y     |
| cde    | Y     | N     | N     | N     | N     |
| dft    | N     | Y     | N     | N     | N     |
| idx    | N     | N     | Y     | N     | N     |
| yhc    | N     | N     | N     | Y     | N     |
+--------+-------+-------+-------+-------+-------+
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