我在Home Controller / Viewmodel类上有以下代码
public class HomeController : SurfaceController {
....
[AllowAnonymous]
public ActionResult LoginIn()
{
var user = new UserDetail() { FirstName = "FirstName", LastName = "LastName" };
UserDetailViewModel model = new UserDetailViewModel() { User = user };
return PartialView("~/Views/Partials/__LoginPartial.cshtml", model);
}
........
}
public class UserDetailViewModel : RenderModel
{
public UserDetailViewModel() : this(new UmbracoHelper(UmbracoContext.Current).TypedContent(UmbracoContext.Current.PageId)) { }
public UserDetailViewModel(IPublishedContent content, CultureInfo culture) : base(content, culture) { }
public UserDetailViewModel(IPublishedContent content) : base(content) { }
public UserDetail User { get; set; }
}
以下是ActionExcuteFilter
[AttributeUsage(AttributeTargets.Class | AttributeTargets.Method, AllowMultiple = false, Inherited = true)] public sealed class ActionExcuteFilter : ActionFilterAttribute {
public override void OnActionExecuting(ActionExecutingContext filterContext)
{
if (HttpContext.Current.Session == null || Convert.ToInt32(HttpContext.Current.Session["UserId"]) ==0)
{
var myAccountPage = uQuery.GetNodesByType("Login").FirstOrDefault();
filterContext.Result = new RedirectToRouteResult(
new RouteValueDictionary {
{ "action", "LoginIn" },
{ "controller", "Home" }});
}
base.OnActionExecuting(filterContext);
} }
并在主页上有以下链接
http://localhost/Products?categoryId=1这是指产品控制者的行为。
因此,如果用户登录,并点击链接一切正常。 (意味着从UmbracoContext获取值并获得相应的页面)
但是当用户点击链接时没有登录麻烦启动(从UmbracoContext获取值时获取错误)
所以执行是:
产品控制器是调用> ActionExcuteFilter> RedirectToRouteResult> Home Controller> LoginIn Action> UserDetailViewModel>给出错误(将UmbracoContext.Current作为null)
所以我想要做的是,当用户尝试访问页面..Product?categoryId = 1而无需登录时,他应该重定向到登录页面。
提前致谢 :)
如果你的UmbracoContext.Current为null,你可以尝试这个,即使它看起来很奇怪。可能SurfaceController不需要非null的UmbracoContext。也许你应该重定向到RenderMvcController
UmbracoContext.EnsureContext(new HttpContextWrapper(HttpContext.Current),
ApplicationContext.Current, true);