我想传递搜索操作的结果,但是我遇到了一个问题,因为它正在返回一个数组,并且该表的所有关系都不起作用
结果视图。为此,我只能通过关系访问表上的数据,而不能访问相关数据]
@extends('layouts.app') @section('content') @foreach ($result as $object) <div class="container"> <div class="row justify-content-center"> <div class="col-md-8"> <div class="card"> <div class="card-header"> <h3>Details for the animal</h3> </div> <div class="card-body"> <div class="col-12"> <p><strong>Id: </strong>{{ $object->id }}</p> </div> </div> </div> </div> </div> </div> @endforeach @endsection
这里是我的控制人
<?php namespace App\Http\Controllers; use App\Animal; use Illuminate\Http\Request; use Illuminate\Support\Facades\DB; class SearchController extends Controller { public function index() { Animal::all(); return view('search.index'); } public function postSearch(Request $request) { $serial_number = $request->input('search'); $this->getResult($serial_number); return redirect()->route('result',$serial_number); } public function getResult($serial_number){ $result = DB::table('slaughters')->where(function ($query) use ($serial_number) { $query->where('id','LIKE',"%$serial_number%"); })->latest()->get(); return view('search.result', ['result'=>$result]); } }
和我的路线
Route::get('/search','SearchController@index')->name('search'); Route::post('/get','SearchController@postSearch'); Route::get('/search/{result}','SearchController@getResult')->name('result');
我也想从与此表相关的表中访问数据。该怎么办
屠宰模型
class Slaughter extends Model
{
protected $guarded = [];
public function user(){
return $this->belongsTo(User::class);
}
public function animal(){
return $this->belongsTo(Animal::class);
}
我想传递搜索操作的结果,但是我遇到了一个问题,因为它正在返回一个数组,并且该表的所有关系都不在工作结果视图中。为此,我可以...
您必须创建模型Slaughter
并定义关系。