我有一个这样的列表:
[('Wed', 1), ('Wed', 1), ('Thu', 1), ('Thu', 0), ('Tue', 0), ('Mon', 0), ('Sun', 0), ('Sat', 0),
('Fri', 0)]
我想要这样的输出:
[('Wed', 2), ('Thu', 1), ('Tue', 0), ('Mon', 0), ('Sun', 0), ('Sat', 0), ('Fri', 0)]
具有列表理解:
>>> l = [('Wed', 1), ('Wed', 1), ('Thu', 1), ('Thu', 0), ('Tue', 0), ('Mon', 0), ('Sun', 0), ('Sat', 0), ('Fri', 0)]
>>> [(x, sum(y[1] for y in l if y[0] == x)) for x in set(z[0] for z in l)]
[('Sun', 0),
('Tue', 0),
('Mon', 0),
('Wed', 2),
('Sat', 0),
('Thu', 1),
('Fri', 0)]
以第二个元素降序排序:
>>> res = [(x, sum(y[1] for y in l if y[0] == x)) for x in set(z[0] for z in l)]
>>> sorted(res, key=lambda x: x[1], reverse=True)
[('Wed', 2),
('Thu', 1),
('Sun', 0),
('Tue', 0),
('Mon', 0),
('Sat', 0),
('Fri', 0)]