如何在 def 函数中移动到列表的下一个字符串？

Question

我正在制作二十一点游戏，需要生成随机牌组。我将每个牌号与每个花色组合起来，直到拥有全部 52 张牌。在我的 def 函数中组合每个卡号和花色，在制作一张卡后，我试图移动到我的卡皮和卡花列表中的下一个字符串。我尝试过使用 next() 函数来执行此操作，但我不知道如何正确使用它们。

import random   #Allows for deck to be shuffled.

def cardsuitandpip(cardpiplist, cardsuitlist):
    for i in range(0, 52):
        card = str(cardpiplist[0] + " of " + cardsuitlist[0])
        deck.append(card)

cardpips = ["2", "2", "2", "2", "3", "3", "3", "3", "4", "4", "4", "4", "5", "5", "5", "5", "6", "6", "6", "6", "7", "7", "7", "7", "8", "8", "8", "8", "9", "9", "9", "9", "10", "10", "10", "10", "Jack", "Jack", "Jack", "Jack", "Queen", "Queen", "Queen", "Queen", "King", "King", "King", "King", "Ace", "Ace", "Ace", "Ace"]
cardsuits = ["Spades", "Clubs", "Hearts", "Diamonds", "Spades", "Clubs", "Hearts", "Diamonds", "Spades", "Clubs", "Hearts", "Diamonds", "Spades", "Clubs", "Hearts", "Diamonds", "Spades", "Clubs", "Hearts", "Diamonds", "Spades", "Clubs", "Hearts", "Diamonds", "Spades", "Clubs", "Hearts", "Diamonds", "Spades", "Clubs", "Hearts", "Diamonds", "Spades", "Clubs", "Hearts", "Diamonds", "Spades", "Clubs", "Hearts", "Diamonds", "Spades", "Clubs", "Hearts", "Diamonds", "Spades", "Clubs", "Hearts", "Diamonds", "Spades", "Clubs", "Hearts", "Diamonds"]
deck = []

deckgenerator = (cardsuitandpip(cardpips, cardsuits))

Answer 1

您的代码距离成功仅一步之遥（如下更改您的相应代码）：

card = str(cardpiplist[i] + " of " + cardsuitlist[i])

此外，您可以简化代码（达到相同的结果）：

cardpips = [val for val in ["2", "3", "4", "5", "6", "7", "8", "9", "10", "Jack", "Queen", "King", "Ace"] for i in range(4)]
cardsuits = 13 * ["Spades", "Clubs", "Hearts", "Diamonds"]