我的字典就是这样
proj_d = {
'key_A:': [u'1361808,1359404,1357929'],
'key_B:': [u'1361808,1359404,1357929'],
'Key_C:': [u'1361808,1359404,1357929'],
'Key_D:': [u'1361808,1359404,1357929']
}
这是方法的返回格式。
我受阻的区域是迭代每个列表中的项目,因为无法使用索引值和键字符串访问列表。
需要协助拆开清单中的物品。
我正在使用python 2.7(如果需要,我可以切换到python 3.7)
列表中的项目是字符串,这就是为什么您需要先使用split
将它们分开的原因。另外,您还提到可以切换到Python3.7,我建议您这样做,因为Python2.7在一月份就已经寿终正寝。
for k, v in proj_d.items():
print(f"Currently inside key {k}")
for val in v[0].split(','):
print(f"Currently at value {val}")
Currently inside key key_A:
Currently at value 1361808
Currently at value 1359404
Currently at value 1357929
Currently inside key key_B:
Currently at value 1361808
Currently at value 1359404
Currently at value 1357929
Currently inside key Key_C:
Currently at value 1361808
Currently at value 1359404
Currently at value 1357929
Currently inside key Key_D:
Currently at value 1361808
Currently at value 1359404
Currently at value 1357929
为了使其更通用,您的列表可以容纳多个字符串,请将其更改为以下字符串。
from itertools import chain
for k, v in proj_d.items():
print(f"Currently inside key {k}")
vals = (item.split(',') for item in v)
for val in chain.from_iterable(vals):
print(f"Currently at value {val}")