如何按照学生在Python上的平均水平使用学生的功能

Question

这里是一个问题：“使用程序功能为5个学生获得姓名，姓氏和4个分数，并最终按平均水平打印出学生的姓名。”

我编写了函数，所以我可以获得每个学生的平均值。但我不知道该如何对学生的姓名进行排序。

_firstname = []
_familiname = []
_scores = []

def student1():
    input('Please enter the firstname:')
    input('Please enter the familiname:')
    for i in range(0, 4):
        scores = int(input('Please enter the scores:'))
        _scores.append(scores)
    b = sum(_scores)
    avg1 = b/4
    print('avg is',avg1)

def student2():
    input('Please enter the firstname:')
    input('Please enter the familiname:')
    for i in range(0, 4):
        scores = int(input('Please enter the scores:'))
        _scores.append(scores)
    b = sum(_scores)
    avg2 = b/4
    print('avg is',avg2)

def student3():
    input('Please enter the firstname:')
    input('Please enter the familiname:')
    for i in range(0, 4):
        scores = int(input('Please enter the scores:'))
        _scores.append(scores)
    b = sum(_scores)
    avg3 = b/4
    print('avg is',avg3)

def student4():
    input('Please enter the firstname:')
    input('Please enter the familiname:')
    for i in range(0, 4):
        scores = int(input('Please enter the scores:'))
        _scores.append(scores)
    b = sum(_scores)
    avg4 = b/4
    print('avg is',avg4)

def student5():
    input('Please enter the firstname:')
    input('Please enter the familiname:')
    for i in range(0, 4):
        scores = int(input('Please enter the scores:'))
        _scores.append(scores)
    b = sum(_scores)
    avg5 = b/4
    print('avg is',avg5)

student1()
student2()
student3()
student4()
student5()

Answer 1

这显然是家庭作业，但这是一个起点：

scores = {90:'best', 80:'good', 60:'ehh'}

ordered_scores = sorted(scores.keys())
print('ordered_scores', ordered_scores)

for score in ordered_scores:
    print('score', score, 'student', scores[score])

给你

ordered_scores [60, 80, 90]
score 60 student ehh
score 80 student good
score 90 student best

查看是否可以更改排序顺序。祝你好运！