如何将Azure Function HttpRequest体转换为对象？

Question

我已经在经典的web apis中做了好几次，但在Azure Functions中没有，所以我不知道我在这里缺少什么。

我的实体 "用户":

[SharedCosmosCollection("shared")]
    public class User : ISharedCosmosEntity
    {
        /// <summary>
        /// User id
        /// </summary>
        [JsonProperty("Id")]
        public string Id { get; set; }

        /// <summary>
        /// Cosmos entity name for shared collection
        /// </summary>
        [CosmosPartitionKey]
        public string CosmosEntityName { get; set; }

        public string GivenName { get; set; }
        public string FamilyName { get; set; }
        public string NickName { get; set; }
        public string Name { get; set; }
        public string Picture { get; set; }
        public string Locale { get; set; }
        public DateTime UodatedAt { get; set; }
        public string Email { get; set; }
        public bool EmailVerified { get; set; }
        public string Sub { get; set; }

    }

我的函数代码为CreateUser:

[FunctionName("CreateUser")]
        public static async Task<IActionResult> CreateUser(
         [HttpTrigger(AuthorizationLevel.Function,
                "post", Route = "user")]
            HttpRequest req)
        {
            var telemetry = new TelemetryClient();
            try
            {
                string requestBody = await new StreamReader(req.Body).ReadToEndAsync();
                var input = JsonConvert.DeserializeObject<User>(requestBody);
                var userStore = CosmosStoreHolder.Instance.CosmosStoreUsers;                
                var added = await userStore.AddAsync(input);
                return new OkObjectResult(added);
            }
            catch (Exception ex)
            {
                string guid = Guid.NewGuid().ToString();
                var dt = new Dictionary<string, string>
                {
                    { "Error Lulo: ", guid }
                };

                telemetry.TrackException(ex, dt);
                return new BadRequestResult();
            }
        }  

而在门户中，我在请求体中发送了这个JSON

{
  "given_name": "aaa",
  "family_name": "bbb",
  "nickname": "xx.xx.psg",
  "name": "bbbb",
  "picture": "https://lh3.googleusercontent.com/a-/AOhsGg8qaBLDPubSaNb3u8zMyiUGrwFE3zhQ8MMqLALjGc",
  "locale": "es",
  "updated_at": "2020-04-20T15:33:16.133Z",
  "email": "[email protected]",
  "email_verified": true,
  "sub": "google-oauth2|1111"
}

但是，我得到了一个http 500错误，不知道是什么问题。

Answer 1

如果类属性与JSON属性不完全匹配，序列化器就无法将JSON属性与类属性匹配，没有一点帮助。 要将JSON属性映射到类属性，可以使用 JsonProperty 属性。这将适用于序列化和反序列化。

[JsonProperty("given_name")]
public string GivenName { get; set; }