如何将属性复制使用声明科特林不同类型的2个列表之间?

问题描述 投票:0回答:2

Context

使用在一个科特林声明性方法,需要从name对象List单个User属性复制到基于匹配List属性UserDetail对象的id,如下所示:

val users = Arrays.asList(
        User(1, "a"),
        User(2, "b")
)
val details = Arrays.asList(
        UserDetail(1),
        UserDetail(2)
)
val detailsWithName = copyNameToUser(users, details)

型号有:

class User {
    var id = -1;
    var name = "" // given for all Users
    constructor(id: Int, name: String)
    // ...
}
class UserDetail {
    var id = -1;
    var name = "" // blank for all UserDetails
    constructor(id: Int)
    // ...
}

Problem

试图通过forEach迭代函数使用声明方式:

fun copyNameToDetails(users: List<User>, details: List<UserDetail>): List<UserDetail> {
    details.forEach(d ->
        users.forEach(u ->
            if (d.id == u.id) {
                d.name = u.name
            }
        )
    )
    return details
}

这可以在Java中实现,如下图所示:

private static List<UserDetail> copyNameToDetails(List<User> users, List<UserDetail> details)   {
    for (UserDetail d: details) {
        for (User u : users) {
            if (d.id == u.id) {
                d.name = u.name;
            }
        }
    }
    return details;
}

Question

这怎么能在科特林以声明的方式来完成?

android kotlin foreach declarative
2个回答
5
投票

你让过两个列表(users.size * details.size),因此创建一个HashMap可以修复它有点太多次迭代:

fun copyNameToUsers(users: List<User>, details: List<UserDetail>): List<UserDetail> {
    val usersById = users.associate { it.id to it }
    details.forEach { d ->
        usersById[d.id]?.let { d.name = it.name }
    }

    return details
}

1
投票

另一方法与非可变值:

data class User(val id: Int = -1, val name: String = "")
data class UserDetail(val id: Int = -1, val name: String = "")

private fun List<UserDetail>.copyNameToUser(users: List<User>): List<UserDetail> = map { userDetail ->
    users.firstOrNull { userDetail.id == it.id }?.let { userDetail.copy(name = it.name) } ?: userDetail
}
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