我有一个浮点数12634.0作为持续时间的结果。我想将其转换为以下格式:月份:天:小时:分钟:秒(00:00:03:30:34)
我怎样才能做到这一点?谢谢
你可以试试
import datetime
print (str(datetime.timedelta(seconds=12634))
另一种解决方案,如果您需要其他信息,如周:
import datetime
def time_in_sec(time_sec):
delta = datetime.timedelta(seconds=time_sec)
delta_str = str(delta)[-8:]
hours, minutes, seconds = [int(val) for val in delta_str.split(":", 3)]
weeks = delta.days // 7
days = delta.days % 7
return "{}:{}:{}:{}:{}".format(weeks, days, hours, minutes, seconds)
def time_in_sec2(seconds):
WEEK = 60 * 60 * 24 * 7
DAY = 60 * 60 * 24
HOUR = 60 * 60
MINUTE = 60
weeks = seconds // WEEK
seconds = seconds % WEEK
days = seconds // DAY
seconds = seconds % DAY
hours = seconds // HOUR
seconds = seconds % HOUR
minutes = seconds // MINUTE
seconds = seconds % MINUTE
return "{}:{}:{}:{}:{}".format(weeks, days, hours, minutes, seconds)
def main():
print(time_in_sec(12634.0))
print(time_in_sec2(12634.0))
结果是:
0:0:3:30:34
0.0:0.0:3.0:30.0:34.0
如果您不想要数周的信息,那么您可以简单地删除它
如果你不想要依赖,你可以采取解决方案2(time_in_sec2)
import datetime