我正在使用下面的代码来提取文件,如下所示,但是我看到正在创建其他文件夹,有人可以帮助我为什么要创建额外的文件夹。
我的文件为abc.zip,其中包含文件sql.db,因此理想情况下,我需要将文件夹文件作为abc / sql.db,但是当我使用以下代码提取时,我将文件夹获取为acb / abc / sql.db,为什么我正在创建此额外的文件夹
def unzip_artifact( local_directory, file_path ):
fileName, ext = os.path.splitext( file_path )
if ext == ".zip":
print 'unzipping file ' + basename(fileName) + ext
try:
with zipfile.ZipFile(file_path) as zf:
for member in zf.infolist():
# Path traversal defense copied from
# http://hg.python.org/cpython/file/tip/Lib/http/server.py#l789
words = member.filename.split('/')
path = local_directory
for word in words[:-1]:
drive, word = os.path.splitdrive(word)
head, word = os.path.split(word)
if word in (os.curdir, os.pardir, ''): continue
path = os.path.join(path, word)
zf.extract(member, path)
except zipfile.error, e:
print "Bad zipfile: %s" % (e)
return
通常,解压缩文件会为您创建目录。因此,如果.zip文件中包含abc目录,那么您正在构建的路径就很麻烦。试试:
def unzip_artifact( local_directory, file_path ):
fileName, ext = os.path.splitext( file_path )
if ext == ".zip":
print 'unzipping file ' + basename(fileName) + ext
try:
with zipfile.ZipFile(file_path) as zf:
for member in zf.infolist():
# Path traversal defense copied from
# http://hg.python.org/cpython/file/tip/Lib/http/server.py#l789
zf.extract(member, local_directory)
except zipfile.error, e:
print "Bad zipfile: %s" % (e)
return
或者更好的是使用extractall:
def unzip_artifact( local_directory, file_path ):
fileName, ext = os.path.splitext( file_path )
if ext == ".zip":
print 'unzipping file ' + basename(fileName) + ext
try:
zipfile.ZipFile(file_path).extractall(local_directory)
except zipfile.error, e:
print "Bad zipfile: %s" % (e)
return
def extracter(file_name, extraction_path):
"""
Common method to extract tar files parameter includes source directory and destination directory
:param file_name:
:param extraction_path:
"""
if not file_name.exists():
print("Oops, file doesn't exist!")
else:
if tarfile.is_tarfile(file_name):
tf = tarfile.open(file_name, 'r:*')
tf.extractall(extraction_path)
tf.close()
使用源方法和目标方法调用该方法。它处理所有类型的tar文件。不需要额外的文件处理。