从java中的文本文件中读取字符串和整数

问题描述 投票:0回答:1
/*This assignment is to create 2 parallel arrays – jobs& salaries
*Read file from “careers.txt” into arrays
*one line – job
*next line –salary
*Sort Salaries {from highest}
*then swap jobs if salary swapped
*Display output of careers and salaries from the highest on a formatted table.
* 
 */
package assignment7;
import java.util.*;//importing Scanner


public class Coordinator 
{


    public static void main(String[] args) throws Exception
    {// the main method creates the arrays and calls on each method to perform 
        //its work.
     String [] job = new String[20];//creating a string array having 20 spaces
     int[] salary = new int[20];//creating an integer array having 20 spaces
     int count;// number of spaces actually occupied in the array

     **count = readFile(job, salary);**// calling a method to read text into both
                                   //arrays and return the number of spaces 
                                   //occupied in the array

     sorter(job,salary,count);// calling on method to arrange file from highest
     //to lowest

     display(job, salary,count);// calling on method present the output


    }
    public static int readFile(String[] jobber, int[] salaro) throws Exception
    { // this method reads a text file and copies into arrays and also
        //returns the number of spaces occupied in the array
            int n = 0; //keeps track of number of times a line is fed into an 
            //array

            //set up a file class object linked up to the name of the file to 
            //be read
            java.io.File unread = new java.io.File("career.txt");

            // create a scanner instance to read the input from the file
            Scanner infile = new Scanner(unread);

            /*This while loop reads line of text into the arrays, it uses 
             * boolean
             * function hasNextLine() and the created scanner instance.
             */
            while (infile.hasNextLine() || infile.hasNextInt())
            {
                jobber[n] = infile.nextLine();
                **salaro[n] = infile.nextInt()**;
                n++;
            }//end while
            infile.close();//close scanner class
            return n;// return number of spaces filled

    }//end of readFile method


    public static void sorter(String[] jobestic, int[] salawe, int z) 
            throws Exception
    {// this method sorts the array from the highest paid job to the lowest.

      boolean swapped;// keeps track of when a swap takes place
      int i;// variable fo for loop
      int temp;// helps in swap
      String temp2;// helps in swap

      do
      {
          swapped = false;
          for (i= 0; i < z-1; i++)// a pass through the array
          {
              if (salawe[i+1] > salawe[i])
              // if the number before it is less they swap
              {
                  //swap starts
                  temp = salawe[i+1];
                  salawe[i+1] = salawe[i];
                  salawe[i] = temp;
                  //swaps the jobs too if the salary is swapped
                  temp2 = jobestic[i+1];
                  jobestic[i+1] = jobestic[i];
                  jobestic[i] = temp2;

                  swapped = true;
              }// end if


          }// end for

      } while (swapped);
   }// end sorter method

   public static void display(String[] jobo, int[] salary5 ,int k) throws Exception
   {

       //this method displays the output as a formatted table
       int i;
       System.out.printf("%-60s%15s%n", "Job", "Salary");





       for(i=0; i<k; i++)



           System.out.printf("%-60s%,15d%n", jobo[i], salary5[i]);

   }








}

请大家,这段代码有什么问题?我一遍又一遍地绞尽脑汁,无法弄清楚出了什么问题......我运行了这段代码,但我一直在犯错......错误总是表明粗线。我试图读取的文本文件如下。我想将作业标题存储在一个数组中,并将相应的工资存储在另一个数组中。像并行数组一样。请问代码有什么问题?我想将工资存储为整数,因为我在呈现输出时将其格式化为整数。谢谢。

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错误:

Exception in thread "main" java.util.InputMismatchException 
at java.util.Scanner.throwFor(Scanner.java:909) 
at java.util.Scanner.next(Scanner.java:1530) 
at java.util.Scanner.nextInt(Scanner.java:2160) 
at java.util.Scanner.nextInt(Scanner.java:2119) 
at assignment7.Coordinator.readFile(Coordinator.java:56)
at assignment7.Coordinator.main(Coordinator.java:25)
java text-files
1个回答
0
投票

这个问题或其等价物似乎每隔几天就被问到一次。

当您拨打nextInt()时,您的扫描仪会在号码后停止。然后当你之后立即调用nextLine()时,你实际上是在行号末尾读取新行字符。你不是在读下一行。因此,在循环的下一次迭代中,当您在扫描仪中接下来排列非数字文本时,您将调用nextInt()

在每次调用nextLine()之后添加额外的调用nextInt(),只是为了读取额外的换行符。

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