井字棋获胜检查不会执行

Question

我正在用 Python 制作一个 tic tac toe 游戏。我已经实现了胜利检查，但每次我在游戏中获得对角线、水平或垂直胜利时，它都不会做它应该做的事情（又名打印“你赢了！”并中断）。这是额外信息的代码（抱歉，有些行不在代码块中。我尝试修复它，但它不会改变。）：

from numpy import array

board = [
    [0,0,0],
    [0,0,0],
    [0,0,0]
]

turn = 1

while True:
    print(board)

    row = int(input('Row: '))
    column = int(input('Column: '))

    board[row,column] = turn

    if turn == 1:
        turn += 1
    else:
        turn -= 1

    if (board[0,0] != 0 and board[1,1] != 0 and board[2,2] != 0) or (board[0,2] != 0 and board[1,1] != 0 and board[2,0]): #diagonals
        if (board[0,0] != 0 and board[0,1] != 0 and board[0,2] != 0) or (board[1,0] != 0 and board[1,1] != 0 and board[1,2] != 0) or (board[2,0] != 0 and board[2,1] != 0 and board[2,2] != 0): #columns
            if (board[0,0] != 0 and board[1,0] != 0 and board[2,0] != 0) or (board[0,1] != 0 and board[1,1] != 0 and board[2,1] != 0) or (board[0,2] != 0 and board[1,2] != 0 and board[2,2] != 0): #rows
                print('\nYou Win!\n')
                break

Answer 1

您的 if 表达式在逻辑上不必要地复杂，因此很容易出错。 Numpy 提供了一种更清晰的方法，如下例所示：

import numpy as np

board = np.array([
    [0,0,1],
    [1,1,0],
    [1,0,1]
])

a = any(sum(board) == 3)  # any of columns
b = any(sum(board.T) == 3) # any of rows
c = (np.trace(board) == 3) # right diagonal
d = (np.trace(np.rot90(board)) == 3) #left diagonal

if a or b or c or d:
    print('Win!')

由于示例中的对角线而打印

Win!