如何监视ubuntu上systemd运行的sidekiq进程?
具体来说,monit文件的外观如何?(我在任何地方都没有看到供sidekiq使用的pidfile)
版本:
ubuntu 18.04.4
sidekiq 6.0.6
monit 5.27.0
sidekiq.service:
[Unit]
Description=sidekiq
After=syslog.target network.target
[Service]
Type=notify
WatchdogSec=10
WorkingDirectory=/var/www/develop/my_app/current
ExecStart=/usr/local/rvm/bin/rvm-exec 2.5.3 bundle exec sidekiq -e develop
ExecReload=/usr/bin/kill -TSTP $MAINPID
# !!! Change this to your deploy user account !!!
User=www-data
Group=www-data
UMask=0002
# Greatly reduce Ruby memory fragmentation and heap usage
# https://www.mikeperham.com/2018/04/25/taming-rails-memory-bloat/
Environment=MALLOC_ARENA_MAX=2
# if we crash, restart
RestartSec=1
Restart=on-failure
# https://www.freedesktop.org/software/systemd/man/systemd.exec.html#StandardOutput=
StandardOutput=file:/var/www/develop/my_app/shared/log/sidekiq.log
StandardError=file:/var/www/develop/my_app/shared/log/sidekiq.log
# This will default to "bundler" if we don't specify it
SyslogIdentifier=sidekiq
[Install]
WantedBy=multi-user.target
/ etc / monit / develop / my_app / myapp_develop_sidekiq:
check process myapp_develop_sidekiq ??? <- what comes here?
start program = "/bin/systemctl start sidekiq" as uid root
stop program = "/bin/systemctl stop sidekiq" as uid root
if cpu > 80% for 5 cycles then restart
if totalmem > 16 GB for 15 cycles then restart
if 3 restarts within 5 cycles then timeout
group all_develop
也许您想要类似的东西:
ExecStartPost=echo $MAINPID > /var/run/sidekiq.pid
ExecStopPost=rm /var/run/sidekiq.pid