如何在不使用pivot和unpivot的情况下在SQL Server中水平显示数据?

问题描述 投票:1回答:2

有没有办法在不使用pivot和unpivot方法的情况下在sql中显示水平数据?下图是使用pivot和unpivot的示例,但我想知道还有其他方法吗?

Example

原始数据

+----+-------+-----------------+
| id | Place | Location        |
+----+-------+-----------------+
|  1 |  CP01 | 3.1415,101.7231 |
|  2 |  CP02 | 3.2314,101.3254 |
|  3 |  CP03 | 3.9415,101.0192 |
|  4 |  CP04 | 3.5490,102.0435 |
|  5 |  CP05 | 3.2562,101.2597 |
|  6 |  CP06 | 3.1134,102.5915 |
+----+-------+-----------------+

Horizontal Data

+----------+-----------------+-----------------+-----------------+-----+
| Cols     | 1               | 2               | 3               | ... |
+----------+-----------------+-----------------+-----------------+-----+
| Location | 3.1415,101.7231 | 3.2314,101.3254 | 3.9415,101.0192 | ... |
|    Place | CP01            | CP02            | CP03            | ... |
+----------+-----------------+-----------------+-----------------+-----+

Image for clarification

sql sql-server pivot
2个回答
0
投票

你可能会寻找这样的东西:

DECLARE @GeoData TABLE (Id INT, Place VARCHAR(10), [Location] VARCHAR(100))

INSERT INTO @GeoData

 SELECT 1,'CP01','3.1415,101.7231' 
 UNION ALL
 SELECT 2,'CP02','3.2314,101.3254'

SELECT  'Location' AS Cols,
        MAX(CASE WHEN t.Id = 1 THEN t.Location END) AS [1],
        MAX(CASE WHEN t.Id = 2 THEN t.Location END) AS [2],
        MAX(CASE WHEN t.Id = 2 THEN t.Location END) AS [3]      
 FROM @GeoData t

 UNION ALL

 SELECT  'Place' AS Cols,
        MAX(CASE WHEN t.Id = 1 THEN t.Place END) AS [1],
        MAX(CASE WHEN t.Id = 2 THEN t.Place END) AS [2],
        MAX(CASE WHEN t.Id = 2 THEN t.Place END) AS [3]     
 FROM @GeoData t

0
投票

类似的方法是你可以使用交叉应用与一些条件聚合,以实现pivotunpivot方式

SELECT a.Col1, MAX(case when a.ID = 1 then a.Value end) [1],
               MAX(case when a.ID = 2 then a.Value end) [2],
               MAX(case when a.ID = 3 then a.Value end) [3]
FROM table T
CROSS APPLY (VALUES ('Place', T.place, T.ID),
                    ('Location', T.Location, T.ID)
            ) as a(Col1, Value, ID)
group by a.Col1
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