MS Access：打开2016 Excel和getObject

Question

在过去的几个小时里，我一直在努力解决这个问题，并尝试了多种解决方案无济于事。我正在尝试在MS Access中打开excel 2016（64位）报告，默认的Excel是2003，现在必须保持这种状态。我的代码是：

Dim xlTmp As excel.Application
Shell ("C:\Program Files\Microsoft Office\root\Office16\EXCEL.exe")
Set xlTmp = GetObject(, "Excel.Application")

这段代码完全符合我的要求，只有当我在调试模式中踩到时，因为excel在尝试抓取对象之前并没有完全启动。如果正常运行会引发错误：

运行时错误'429'ActiveX组件无法创建对象

我尝试了以下一些解决方案无济于事：

Function OpenExcel()
   x = Shell("C:\Program Files\Microsoft Office\root\Office16\EXCEL.exe", vbNormalFocus)
   OpenExcel = x
End Function

Function GetOpenExcel() As excel.Application
    Set GetOpenExcel = GetObject(, "Excel.Application.16")

TryAgain:
    On Error GoTo NoExcel
    Set xlTmp = GetObject(, "Excel.Application.16")
    On Error GoTo 0
    xlTmp.Visible = True
    Set GetOpenExcel = xlTmp
Exit Function

NoExcel:
    Resume TryAgain
End Function

还有这个

Set ie = Nothing
cnt = 0

cnt = xlTmp.Windows.count
sh = Shell("C:\Program Files\Microsoft Office\root\Office16\EXCEL.exe",     vbNormalFocus)
Do Until xlTmp.Windows.count = cnt + 1
Loop
Set xlTmp = GetObject("excel.Application.16")
Set sh = xlTmp.Windows(xlTmp.Windows.count - 1)

我也尝试过转换我的参考文献，有点困惑，但这是我现在所拥有的：MS Access References

在此先感谢，任何帮助将不胜感激。

Answer 1

只是用

Set xlTmp = CreateObject("Excel.Application")

而不是GetObject

UPDATE

这段代码对我有用，我有默认2016而不是默认2010：

Private Sub Command0_Click()
Dim xlTmp As Object
Shell "D:\Program Files (x86)\Microsoft Office 2010\Office14\EXCEL.EXE", vbNormalFocus

TryAgain:
    On Error GoTo NoExcel
    Set xlTmp = GetObject(, "Excel.Application")
    On Error GoTo 0
    'here I received correct xlTmp
Exit Sub

NoExcel:
    Resume TryAgain
End Sub