awk命令来分析由新行分隔的文件

Question

我的输入文件如下：

OS ABI

   UNIX - System V

CPU Class

   64-bit

Persistence (user)

   No

File type 

   ELF 32-bit MSB executable, PowerPC or cisco 4500, version 
   (SYSV),statically linked, not   stripped,32-bit MSB executable, 
   PowerPC or cisco 4500, version (SYSV),statically linked, not stripped

CPU Type

  PowerPC

我希望输出为：

OS ABI UNIX - System V
CPU CLASS 64-bit
Persistence (user) No
File Type ELF 32-bit MSB executable, PowerPC or cisco 4500, version (SYSV),statically linked, not   stripped,32-bit MSB executable, PowerPC or cisco 4500, version (SYSV),statically linked, not stripped 
CPU Type PowerPC

请使用awk建议脚本/命令，该脚本/命令可以输出所需的结果？当我们必须解析字段5中所示的多行时，问题就来了。我也希望对每个字段中的行数进行计数，例如：字段1有一行，字段5有2等。

Answer 1

这将为您完成：

awk 'BEGIN{RS=""}
     !/^[[:blank:]]/{printf $0 OFS; next}
     { gsub(/(^|\n)[[:blank:]]+/,OFS) }1' file

Answer 2

EDIT：

Answer 3

另一个awk变体：

Answer 4

$ awk -v RS= '{gsub(/[[:space:]]+/," "); printf "%s%s", $0, (NR%2?"":ORS)}' file
OS ABI UNIX - System V
CPU Class 64-bit
Persistence (user) No
File type  ELF 32-bit MSB executable, PowerPC or cisco 4500, version (SYSV),statically linked, not stripped,32-bit MSB executable, PowerPC or cisco 4500, version (SYSV),statically linked, not stripped
CPU Type PowerPC