我想将以下
JSON
字符串转换为 Java
对象:
{
"user": {
"0": {
"firstName": "Monica",
"lastName": "Belluci"
},
"1": {
"firstName": "John",
"lastName": "Smith"
},
"2": {
"firstName": "Owen",
"lastName": "Hargreaves"
}
}
}
为了将其转换为
Java
对象,我创建了以下类:
class User {
private Map<String, MyObject> user = new HashMap<>();
//Getter and Setter is here
}
class MyObject {
private String firstName;
private String lastName;
//Getters and Setters are here
}
我正在使用 Jackson 库将
JSON
转换为 Java
。以下是我如何使用 Jackson 进行转换:
ObjectMapper mapper = new ObjectMapper();
User user = mapper.readValue(jsonString, User.class);
问题是,通过上面的转换,用户对象内的
Map
始终为空。我做错了什么?
提前致谢。
我认为应该有效。我已经执行了这段代码并且运行良好。这是我的例子。
import com.fasterxml.jackson.databind.ObjectMapper;
import java.io.IOException;
public class TestJackson {
public static void main(String[] args) throws IOException {
ObjectMapper mapper = new ObjectMapper();
String testJson = "{\n" + " \"user\": {\n" + " \"0\": {\n" + " \"firstName\": \"Monica\",\n" + " \"lastName\": \"Belluci\"\n" + " },\n" + " \"1\": {\n" + " \"firstName\": \"John\",\n" + " \"lastName\": \"Smith\"\n" + " },\n" + " \"2\": {\n" + " \"firstName\": \"Owen\",\n" + " \"lastName\": \"Hargreaves\"\n" + " }\n" + " }\n" + "}";
User readValue = mapper.readValue(testJson, User.class);
System.out.println("readValue = " + readValue);
}
}
和 User.class:
import java.util.HashMap;
import java.util.Map;
class User {
private Map<String, MyObject> user = new HashMap<String, MyObject>();
public Map<String, MyObject> getUser() {
return user;
}
public void setUser(Map<String, MyObject> user) {
this.user = user;
}
@Override
public String toString() {
return "User{" +
"user=" + user +
'}';
}
}
class MyObject {
private String firstName;
private String lastName;
public String getFirstName() {
return firstName;
}
public void setFirstName(String firstName) {
this.firstName = firstName;
}
public String getLastName() {
return lastName;
}
public void setLastName(String lastName) {
this.lastName = lastName;
}
@Override
public String toString() {
return "MyObject{" +
"firstName='" + firstName + '\'' +
", lastName='" + lastName + '\'' +
'}';
}
}
使用可以在 gson 库的帮助下完成。
import java.io.IOException;
import java.io.InputStreamReader;
import java.io.Reader;
import com.google.gson.Gson;
import com.google.gson.GsonBuilder;
public class JsonToJava {
public static void main(String[] args) throws IOException {
try(Reader reader = new InputStreamReader(JsonToJava.class.getResourceAsStream("/Server2.json"), "UTF-8")){
Gson gson = new GsonBuilder().create();
Person p = gson.fromJson(reader, YourPOJOClass.class);
System.out.println(p);
}
}
}
访问此链接希望这有帮助:)
我在将 JSON 转换为 Java POJO 时遇到了一个额外问题:
com.fasterxml.jackson.databind.JsonMappingException: Can not deserialize instance of class out of START_ARRAY token ...
如果有人遇到此问题,这是因为 JSON 需要一个
object {}
,但它在传入的 JSON 字符串中看到一个 array [{}]
ObjectMapper mapper = new ObjectMapper();
User user = mapper.readValue(jsonString, User.class);
修复
User[] user = mapper.readValue(jsonString, User[].class);
您可以尝试下面的代码,效果很好..
public class User {
private Map<String, Map<String, String>> user;
public Map<String, Map<String, String>> getUser() {
return user;
}
public void setUser(Map<String, Map<String, String>> user) {
this.user = user;
}
}
public class JsonCast {
public static void main(String args[]) {
String response = "{\"user\" : {\"0\": {\"firstName\": \"Monica\",\"lastName\": \"Belluci\"},\"1\": { \"firstName\": \"John\",\"lastName\": \"Smith\"}}}";
ObjectMapper mapper = new ObjectMapper();
try {
User user = mapper.readValue(response, User.class);
System.out.println(user.getUser().get("0"));
} catch (IOException e) {
e.printStackTrace();
}
}
}
尝试将 json 字符串粘贴到 this 链接,它将完成剩下的工作,编写所需的类。